问题描述
<label for='order-number'>Order Number: </label>
<select name='orderNumber' id='order-number'>
<option></option>
<?PHP
// Select all order numbers
$query_orderNumber = "SELECT orderNumber FROM orders ORDER BY orderNumber ASC";
// Store them into $order_numbers
$order_numbers = MysqLi_query($connection,$query_orderNumber);
while ($row = MysqLi_fetch_assoc($order_numbers)) {
$num = $row['orderNumber'];
$selected = (isset($_POST['orderNumber']) && ($_POST['orderNumber']=='$num'))
? "selected='selected'":'';
echo "<option value='$num' ". $selected. " >$num</option>";
}
?>
</select>
我使用数据库中的数据创建了此下拉列表。我想通过PHP提交表单后保留选定的选项。但这并不会保留我选择的选项。
解决方法
您不需要像这样使用'$ num'
$selected = (isset($_POST['orderNumber']) && ($_POST['orderNumber']== $num)) ? "selected='selected'":'';