如何使用xsmtplib代替smtplib发送邮件与xsmtplib一样，不要求输入登录密码

问题描述

根据pipy.org

使用xsmtplib的方法如下：

  from xsmtplib import SMTP<br/>
  server = SMTP(host="smtp.example.com",proxy_host="proxy.example.com")<br/>
  server.sendmail("[e-mail]","[e-mail]","I have an issue. Please help!")<br/>
  server.quit()

但是我想先用密码登录然后发送。
类似于：

    server = xsmtplib.SMTP("smtp.gmail.com",587)<br/>
    server.ehlo()<br/>
    server.starttls()<br/>
    server.ehlo()<br/>
    server.login("[e-mail]","zzzzz")<br/>
    message = f"Dear Sir,\n\nThere is a price drop for your selected product. Current Price is {price}.\n Regards"<br/>
    server.sendmail("[e-mail]","[e-mail]",message)<br/>

解决方法

使用“ xsmtplib.xsmtplib.SMTP”其余部分的答案与smtplib相似。

server = xsmtplib.xsmtplib.SMTP("smtp.gmail.com",587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("[e-mail]","zzzzz")<br/>
message = f"Dear Sir,\n\nThere is a price drop for your selected product. Current Price is {price}.\n Regards"
server.sendmail("[e-mail]","[e-mail]",message)