问题描述
我是使用sql的初学者,我想知道是否有人可以提供帮助。 我有2张桌子 表1是如下的客户表
> POST http://localhost:8080/api/persons
> WebTestClient-Request-Id: [1]
> Content-Type: [application/json]
> Content-Length: [98]
{
"first_name" : "John","last_name" : "Smith","age" : 25,"calculationSeed" : 0.0
}
< 201 CREATED Created
< Content-Type: [application/json]
< transfer-encoding: [chunked]
< Date: [Mon,19 Oct 2020 15:26:01 GMT]
{"first_name":"John","last_name":"Smith","age":25,"calculation_seed":0.09482345680132348}
表2是一个价值细分
CUSTOMER ID - CUSTOMER JOIN DATE
1234 01/03/2018
2345 21/07/2019
我需要做的是加入“客户”表,并带回“客户ID”和“加入日期”,然后从“价值段”表中取回具有最新“加载日期”的值,这样我的表将如下所示:
CUSTOMER ID - VALUE - LOADED_DATE
1234 HIGH 01/09/20
1234 MEDIUM 01/10/20
2345 LOW 01/09/20
2345 LOW 01/10/20
预先感谢
谢谢, 迈克
解决方法
一个选项可能正在使用row_number()
select * from
(
select cusomer_id,customer_join_date,value,row_number() over(partition by customer_id order by LOADED_DATE desc) as rn
from
customer c inner join value_segment v on c.customer_id=v.customer_id
)A where rn=1
,
具有FIRST_VALUE()
窗口功能:
select distinct c.*,first_value(v.value) over (partition by c.customerid order by v.loaded_date desc) value
from customer c inner join valuesegment v
on v.customerid = c.customerid