禁止在空的Typolink上换行

问题描述

如果键入错误链接出于任何原因(例如缺少页面,隐藏页面...)返回空网址,则给定的键入内容将呈现带有空href属性的import React,{useState} from 'react' import {Link as LinkR} from 'react-router-dom' import './SectionConnect.css' const SectionConnect = () => { return ( <div className="connect-container"> <div className="connect-wrapper"> <h2>How it works</h2> <p>We connect you with the very best practitioners and most effective methods to achieve optimal health.</p> <div className="connect-btn"> <LinkR to='/' onClick={()=>setClick(true)} className={clicked ? 'active-btn':'disable-btn'}> For companies </LinkR> <LinkR to='/forIndividuals' onClick={()=>setClick(!clicked)} className={clicked ? 'disable-btn':'active-btn'}> For individuals </LinkR> </div> </div> </div> ) } export default SectionConnect 标签。

我该如何设置它,以便在url为空(最好没有丑陋的3部分COA ...)的情况下完全不呈现标记?

我尝试使用.connect-btn { display: flex; justify-content: space-around; padding: 8px 8px 6px 10px; background: #FAFAFC; border-radius: 78px; width: 58%; height: 50px; } .disable-btn { font-family: Sofia Pro; font-style: normal; font-weight: 600; font-size: 16px; line-height: 140%; color: #435473; padding: 4px 8px 0px 16px; border-radius: 74px; text-decoration: none; } .active-btn { padding: 8px 8px 0px 16px; background: #5582A7; border-radius: 74px; font-family: Sofia Pro; font-style: normal; font-weight: 600; font-size: 16px; line-height: 140%; color: #FFFFFF; text-decoration: none; } <a href="" ... >foo</a>进行了几种配置,但似乎没有任何作用。

required = 1

解决方法

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