问题描述
如何从父元素中删除任何重复的childNodes,以使父元素中具有相同innerText的元素不超过1个?下面的HTML示例说明了之前和之后的含义。
HTML
<div id="parent">
<div class="child">hello</div>
<div class="child">hello</div>
<div class="child">world</div>
<div class="child">world</div>
</div>
目标
<div id="parent">
<div class="child">hello</div>
<div class="child">world</div>
</div>
解决方法
尝试一下。
var childs = document.querySelectorAll(".child")
var tmpTexts = []
for (const c of childs) {
if (tmpTexts.includes(c.innerText)) continue
tmpTexts.push(c.innerText)
c.parentNode.removeChild(c)
}
<div id="parent">
<div class="child">hello</div>
<div class="child">hello</div>
<div class="child">world</div>
<div class="child">world</div>
</div>
,
这是另一种方法:
const children = document.querySelectorAll('.child');
function filterChildren(text,i,textArray) {
if ( textArray.indexOf(text) <= textArray.lastIndexOf(text) && textArray.indexOf(text) !== i ) {
children[i].parentNode.removeChild( children[i] )
}
}
Array
.from(children)
.map( child => child.innerHTML )
.forEach(filterChildren);
<div id="parent">
<div class="child">hello</div>
<div class="child">hello</div>
<div class="child">world</div>
<div class="child">world</div>
</div>