问题描述
我有以下列表和字符串:
befcodes = ["A1","A2","A3","A4","A5","A6","A7","A8","A9","10","11","12","13","14","15","16","17","18","19","20"]
telegram = "$00;02;A1;00000000*49"
我的代码现在在字符串中A1
更改了20次,如下所示:
allbefcodes = []
for i in befcodes:
dif_tele = telegram.replace("A1",i)
allbefcodes.append(dif_tele)
print (allbefcodes)
哪个输出以下列表:
['$00;02;A1;00000000*49','$00;02;A2;00000000*49','$00;02;A3;00000000*49','$00;02;A4;00000000*49','$00;02;A5;00000000*49','$00;02;A6;00000000*49','$00;02;A7;00000000*49','$00;02;A8;00000000*49','$00;02;A9;00000000*49','$00;02;10;00000000*49','$00;02;11;00000000*49','$00;02;12;00000000*49','$00;02;13;00000000*49','$00;02;14;00000000*49','$00;02;15;00000000*49','$00;02;16;00000000*49','$00;02;17;00000000*49','$00;02;18;00000000*49','$00;02;19;00000000*49','$00;02;20;00000000*49']
现在,我想使用XOR运算符来获取我这样做的每个电报(= allbefcodes
的每个字符)的二进制校验和:
result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))
print (f'{result:08b}')
这对于allbefcodes[0]
确实不错,我得到了输出01001001
。但是我现在想对allbefcodes
的所有字符进行循环处理,这时我会遇到不同的错误。.到目前为止,这是我尝试过的事情:
for x in allbefcodes:
result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))
print (f'{result:08b}')
发生错误TypeError: list indices must be integers or slices,not str
。我试图这样解决:
for x in allbefcodes:
allbefcodes = (int(a) for a in allbefcodes)
result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18])) # "
print (f'{result:08b}')
但是这里出现错误TypeError: 'generator' object is not subscriptable
。所以我接下来尝试了这个:
allbefcodes = []
for i in befcodes:
dif_tele = telegram.replace("A1",i)
allbefcodes.append(dif_tele)
allbefcodes = (int(a) for a in allbefcodes) #Tried to solve it with this line
print (allbefcodes)
for x in allbefcodes:
result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18])) # "(allbefcodes[0])" statt telegram
print (f'{result:08b}')
但是现在出现错误ValueError: invalid literal for int() with base 10: '$00;02;A1;00000000*49'
。进行(float(int(a)) for a in allbefcodes)
不会改变。
我的最后一次尝试是将(allbefcodes[x])
更改为(allbefcodes[0:])
,而将allbefcodes = (int(a) for a in allbefcodes)
留在外面,就像这样:
allbefcodes = []
for i in befcodes:
dif_tele = telegram.replace("A1",i)
allbefcodes.append(dif_tele)
print (allbefcodes)
for x in allbefcodes:
result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18])) # "(allbefcodes[0])" statt telegram
print (f'{result:08b}')
但是现在我得到了TypeError: ord() expected a character,but string of length 21 found
,这使我重新需要整数而不是字符串,我已经尝试解决了...我真的不知道该怎么办了,非常感谢您的帮助!
解决方法
我知道了!
我只需要像这样用(allbefcodes[0:])
替换x
:
allbefcodes = []
for i in befehlscodes:
dif_tele = telegram.replace("A1",i)
allbefcodes.append(dif_tele)
print (allbefcodes)
for x in allbefcodes:
result = functools.reduce(operator.xor,(ord(n) for n in x[1:18]))