问题描述
我有一个属于report_data
表的表daily_entry
,但是当我调用api
想要获取daily_entry
表的所有数据时,它会像下面这样发送响应
{
"response_code": "0","message": "Operation is successfully executed","status": "success","data": {
"id": 1,"user_id": 1,"date": "12-10-2020",other data ....
"is_active": true,"createdAt": "2020-10-21T06:25:57.877Z","updatedAt": "2020-10-21T06:25:57.877Z","report_datum": {
"id": 1,"entry_i": 1,<<<<<<<----------OUTPUT
"Date": null,"report_document_id": "2","createdAt": "2020-10-21T06:26:02.642Z","updatedAt": "2020-10-21T06:26:02.642Z"
}
},"level": "info","timestamp": "2020-10-21T06:25:45.947Z"
}
预期
{
"response_code": "0","report_data": {
"id": 1,"entry_id": 1,<<<<<-------------EXPECTED
"Date": null,"timestamp": "2020-10-21T06:25:45.947Z"
}
两个表之间的关系为hasOne
db.daily_entry.hasOne(db.report_data,{ onDelete: "cascade",foreignKey: 'entry_id',foreignKeyConstraint: true,targetKey: 'id' });
我已经记录了来自数据库的数据,就像下面一样
dataValues:{id: 1,entry_i: 1,daily_entry : 8468476,date: 23-10-2020,…}
get entry_id:ƒ () {\n return this.get(attribute);\n }
undefined
我已经检查了整个项目,没有像entry_i
这样的名称
API I代码在下面
getdaily_entryById: async (req,res) => {
sequelize.sequelize.transaction(async (t1) => {
if (!req.params.id) {
logger.warn(error.MANDATORY_FIELDS)
return res.status(500).send(error.MANDATORY_FIELDS);
}
let data = await sequelize.daily_entry.findOne({
where: { id: req.params.id },include: [
sequelize.report_data
]
});
let result = error.OK
result.data = data
logger.info(result);
return res.status(200).send(result);
}).catch(function (err) {
logger.warn(err)
console.log(err)
return res.status(500).send(error.SERVER_ERROR);
});
}
每日条目 表架构
module.exports = function (sequelize,DataTypes) {
const daily_entry = sequelize.define('daily_entry ',{
user_id: {
type: DataTypes.INTEGER(),allowNull: true
},date: {
type: DataTypes.STRING,report_status: {
type: DataTypes.STRING,high_close: {
type: DataTypes.DOUBLE(),high_open: {
type: DataTypes.DOUBLE(),low_close: {
type: DataTypes.DOUBLE(),low_open: {
type: DataTypes.DOUBLE(),is_active: {
type: DataTypes.BOOLEAN,allowNull: true
}
});
return daily_entry
};
报告数据 表架构
module.exports = function (sequelize,DataTypes) {
const report_data= sequelize.define('report_data',{
daily_entry : {
type: DataTypes.INTEGER(),Date: {
type: DataTypes.INTEGER(),report_document_id: {
type: DataTypes.TEXT,allowNull: true
}
},{
tableName: 'report_data'
});
return report_data
};
所以,我在哪里做错了,为什么要使用entry_i
作为外键
解决方法
尝试将表名更改为 CamelCase ,然后尝试。
我知道这应该是评论,但目前我没有评论的权限