问题描述
我正在尝试扩展由neo4j-graphql-js
自动生成的graphql模式
这是我的graphql模式
typeDefs
type Person {
_id: Long!
addresslocation: Point!
confirmedtime: DateTime!
healthstatus: String!
id: String!
name: String!
performs_visit: [Visit] @relation(name: "PERFORMS_VISIT",direction: OUT)
visits: [Place] @relation(name: "VISITS",direction: OUT)
VISITS_rel: [VISITS]
}
type Place {
_id: Long!
homelocation: Point!
id: String!
name: String!
type: String!
part_of: [Region] @relation(name: "PART_OF",direction: OUT)
visits: [Visit] @relation(name: "LOCATED_AT",direction: IN)
persons: [Person] @relation(name: "VISITS",direction: IN)
}
type Visit {
_id: Long!
duration: String!
endtime: DateTime!
id: String!
starttime: DateTime!
located_at: [Place] @relation(name: "LOCATED_AT",direction: OUT)
persons: [Person] @relation(name: "PERFORMS_VISIT",direction: IN)
}
type Region {
_id: Long!
name: String!
places: [Place] @relation(name: "PART_OF",direction: IN)
}
type Country {
_id: Long!
name: String!
}
type Continent {
_id: Long!
name: String!
}
type VISITS @relation(name: "VISITS") {
from: Person!
to: Place!
duration: String!
endtime: DateTime!
id: String!
starttime: DateTime!
}
现在,我扩展了人员以执行自定义查询,以便使用@cypher
指令
typeDefs2
type Person {
potentialSick: [Person] @cypher(statement: """
MATCH (p:this)--(v1:Visit)--(pl:Place)--(v2:Visit)--(p2:Person {healthstatus:"Healthy"})
return *
""")
}
我通过合并两个typeDef创建模式,并且按预期工作
export const schema = makeAugmentedSchema({
typeDefs: mergeTypeDefs([typeDefs,typeDefs2]),config: {
debug: true,},});
问题
可以从我的自定义查询potentialSick
返回自定义类型(映射在graphql中)吗?
我的目标是返回与此类似的类型
type PotentialSick {
id: ID
name: String
overlapPlaces: [Place]
}
在neo4j查询中,pl
是重叠的位置
MATCH (p:this)--(v1:Visit)--(pl:Place)--(v2:Visit)--(p2:Person {healthstatus:"Healthy"})
解决方法
我意识到neo4j-graphql-js
是一个查询生成器,因此我可以仅通过使用主模式使用graphql来获取数据。我的查询将是:
{
Person(filter: { healthstatus: "Sick" }) {
id
visits {
_id
persons(filter: { healthstatus: "Healthy" }) {
_id
}
}
}
}
考虑到这一原则,对于需要@cyper
的更复杂的查询,我可以扩展每种类型的基本架构并依靠graphql功能
作为示例
type Person {
potentialSick: [Place] @cypher(statement: """
MATCH path =(this)-[:VISITS]->(place:Place)<-[:VISITS]-(p2:Person {healthstatus:"Healthy"})
return place
""")
potentialSick返回places
,然后获得访问那个地方的人,我可以使用graphql
{
Person(filter: { healthstatus: "Sick" }) {
id
potentialSick {
persons (filter: { healthstatus: "Healthy" }){
_id
}
}
}
}