问题描述
我创建了以下HIVE
表,该表有助于从源配置单元表中确定个人的数量和类型。现在,我需要从中创建更多的百分比突破:
CREATE TABLE hh_member_type AS
SELECT count(*) AS count,CASE WHEN (LEAD_HOUSEHLD_STATUS = 'D') THEN 'Deceased'
WHEN (LEAD_HOUSEHLD_STATUS = 'H') THEN 'Head'
WHEN (LEAD_HOUSEHLD_STATUS = 'P') THEN 'Aged Parent At Home'
WHEN (LEAD_HOUSEHLD_STATUS = 'U') THEN 'UnkNown'
WHEN (LEAD_HOUSEHLD_STATUS = 'W') THEN 'Spouse'
WHEN (LEAD_HOUSEHLD_STATUS = 'Y') THEN 'Young Adult' ELSE 'NULL'
END AS HH_STATUS
FROM (
SELECT LEAD_HOUSEHLD_STATUS FROM customer
UNION ALL SELECT MEM1_HH_STATUS FROM customer
UNION ALL SELECT MEM2_HH_STATUS FROM customer
UNION ALL SELECT MEM3_HH_STATUS FROM customer
UNION ALL SELECT MEM4_HH_STATUS FROM customer
UNION ALL SELECT MEM5_HH_STATUS FROM customer
UNION ALL SELECT MEM6_HH_STATUS FROM customer
UNION ALL SELECT MEM7_HH_STATUS FROM customer
UNION ALL SELECT MEM8_HH_STATUS FROM customer)A
WHERE LEAD_HOUSEHLD_STATUS IN ('H','D','P','U','W','Y')
GROUP BY LEAD_HOUSEHLD_STATUS ;
hive> select * from hh_member_type ;
OK
277 Deceased
20636 Head
3547 Aged Parent At Home
18926 UnkNown
16184 Spouse
7082 Young Adult
Time taken: 0.195 seconds,Fetched: 6 row(s)
我尝试使用以下代码创建百分比突破,但未获得所需的输出。任何建议都会很棒。
CREATE TABLE hh_member_percent AS
SELECT a.hh_status,round(a.count/sum(a.count) * 100,2)
from hh_member_type a
group by a.count,a.hh_status ;
解决方法
使用分析功能sum():
SELECT a.hh_status,round(a.count/sum(a.count) over() * 100,2)
from hh_member_type a
;