有什么方法可以将经过过滤的查询集传递到Django的分页中？

问题描述

view.py

def quiz(request):

    question_topic = request.POST.getlist("topic_checkBox") # Retrieves list of topics selected by user
    question_list = Quiz.objects.filter(Topic_name__in = question_topic) #filters out questions by topics

    paginator = Paginator(question_list,1) # when i pass all the objects rather than the filtered query set it seems to work but when i paginate with the filtered queryset only the first page loads
    page = request.GET.get('page')
    try:
        question_list = paginator.page(page)
    except PageNotAnInteger:
        question_list = paginator.page(1)
    except EmptyPage:
        question_list = paginator.page(paginator.num_pages)

    return render(request,"Quiz/quiz_home.html",{"question_list":question_list})

quiz_home.html

{% block content %}
        {% for q in question_list %} # loops through the filtered queryset
            {% if question_list.has_next %}
                <h3>Question {{q.id}}</h3>
                <form method="POST" action="?page={{ question_list.next_page_number }}">{% csrf_token %}
# The form should enable me to gather the users input whilst simultaneoulsy going to the next question in the for loop. But when question sumbitted the next page is blank showing no contents
                    {% if q.picture %}
                        <img src="/media/{{q.picture}}"> <br>
                    {% endif %}
                    {{q.id}}.) </label><label id="question_text">{{q.question}}</label><br>
                    <input type="hidden" id= "q_id" name="q_id" value="{{q.id}}">
                    <input type="hidden" id= "topic" name="topic" value="{{q.topic}}">
                    <input type="radio" id="opt1" name="options" value="{{q.option1}}" required>{{ q.option1 }}<br>
                    <input type="radio" id="opt2" name="options" value="{{q.option2}}" required>{{ q.option2 }}<br>
                    <input type="radio" id="opt3" name="options" value="{{q.option3}}" required>{{ q.option3 }}<br>
                    <hr>
                    <input type="submit" id="mybtn" value="Submit"> #once clicked it should paginate to next page
                </form>
            {% else %}
                <hr>
                <form action="/home/">{% csrf_token %}
                    <input type="submit" name="End" value="End">
                </form>
            {% endif %}
        {% endfor %}
    {% endblock %}

本质上是试图根据用户选择的主题过滤掉问题。然后对这个问题的查询集进行分页，以便每个页面显示一个问题。

解决方法

我将向您展示一个分页实例：

views.py

class CategoryDetail(ListView):  
    model = Task  
    template_name = 'category/category_detail.html'  
    context_object_name = 'task'  
    paginate_by = 5

    def get_queryset(self):
        self.category = get_object_or_404(Category,pk=self.kwargs['pk'])  
        return Task.objects.filter(category=self.category).order_by('-id')  

    def get_context_data(self,*,object_list=None,**kwargs):
        context = super(CategoryDetail,self).get_context_data(**kwargs)
        self.category = get_object_or_404(Category,pk=self.kwargs['pk'])
        # context['category'] = self.category
        return context

category / category_detail.html

....

 <div class="card-footer py-4">
                {% if is_paginated %}
              <nav aria-label="...">
                <ul class="pagination justify-content-end mb-0">
                    {% if page_obj.has_previous %}
                  <li class="page-item">
                    <a class="page-link" href="?page={{ page_obj.previous_page_number }}" tabindex="-1">
                      <i class="fas fa-angle-left"></i>
                      <span class="sr-only">Previous</span>
                    </a>
                  </li>

                   {% else %}

                     <li class="page-item disabled">
                    <a class="page-link" href="#" tabindex="-1">
                      <i class="fas fa-angle-left"></i>
                      <span class="sr-only">Previous</span>
                    </a>
                  </li>

                    {% endif %}

                    {% for i in paginator.page_range %}
                    {% if page_obj.number == i %}
                  <li class="page-item active">
                    <a class="page-link" href="#"> {{ i }} </a>
                  </li>
                     {% else %}
                  <li class="page-item">
                    <a class="page-link" href="?page={{ i }}">{{ i }}<span class="sr-only">(current)</span></a>
                  </li>
                    {% endif %}
                    {% endfor %}

                     {% if page_obj.has_next %}
                  <li class="page-item">
                    <a class="page-link" href="?page={{ page_obj.next_page_number }}">
                      <i class="fas fa-angle-right"></i>
                      <span class="sr-only">Next</span>
                    </a>
                  </li>

                    {% else %}

                     <li class="page-item disabled">
                    <a class="page-link" href="#">
                      <i class="fas fa-angle-right"></i>
                      <span class="sr-only">Next</span>
                    </a>
                  </li>
                    {% endif %}

                </ul>
              </nav>
                {% endif %}
            </div>

Django已经具有现成的分页结构。您可以在要使用的HTML文件中使用它。