问题描述
如何等待QThread
的完成或std::thread::join()
中的QThread
方法的等效方式
在std :: thread中,我可以像下面这样
void foo()
{
// simulate expensive operation
std::cout << "starting first thread1...\n";
std::this_thread::sleep_for(std::chrono::seconds(1));
}
void bar()
{
// simulate expensive operation
std::cout << "starting second thread2...\n";
std::this_thread::sleep_for(std::chrono::seconds(1));
}
int main()
{
std::thread thread1(foo);
std::thread thread2(bar);
std::cout << "waiting for threads to finish..." << std::endl;
thread1.join();
thread2.join();
std::cout << "done!\n";
}
starting first thread1...
waiting for threads to finish...
starting second thread2...
done!
解决方法
谢谢@ Alex F的建议。
这是我当时尝试的:
#include <QApplication>
#include <QThread>
#include "mydialog.h"
#include <QDebug>
void foo()
{
// simulkate a long work
qDebug() << " Starting Qthread1 ..." ;
QThread::msleep(5000);
}
void bar()
{
qDebug() << " Starting Qthread2 ..." ;
QThread::msleep(2000);
}
int main(int argc,char *argv[])
{
QApplication a(argc,argv);
QThread* thread1 = QThread::create(foo);
QThread* thread2 = QThread::create(bar);
// to verify at real-time when the thread finishes
QObject::connect(thread1,&QThread::finished,[](){ qDebug()<< "Thread1 has finished";});
QObject::connect(thread2,[](){ qDebug()<< "Thread2 has finished";});
thread1->start();
thread2->start();
qDebug()<< "Waiting for threads to finish";
thread1->wait();
thread2->wait();
qDebug() << "done";
return a.exec();
}
输出如下:
Waiting for threads to finish
Starting QThread2 ...
Strating QThread1 ...
Thread 2 has finished
Thread 1 has finished