问题描述
以下示例有效。只要不需要JSX,我就可以在没有编译/构建的简单网页中使用普通的React组件。
如果按如下所示链接Fluent UI(.JS和.CSS),是否可以以相同方式使用Fluent UI组件?这似乎不起作用。
<!DOCTYPE html>
<html>
<head>
<title>Index</title>
</head>
<body>
<p>This is a test</p>
<br />
<br />
<p><div class="test_container"></div></p>
<!-- Load React -->
<!-- Note: when deploying,replace "development.js" with "production.min.js". -->
<script src="https://cdn.jsdelivr.net/npm/react@17/umd/react.development.js"></script>
<script src="https://cdn.jsdelivr.net/npm/react-dom@17/umd/react-dom.development.js"></script>
<!-- Load Fabric (Commented out) -->
<!--<link rel="stylesheet" href="https://static2.sharepointonline.com/files/fabric/office-ui-fabric-core/11.0.0/css/fabric.css" />-->
<!--<script src="https://cdn.jsdelivr.net/npm/office-ui-fabric-react@7.149.0/dist/office-ui-fabric-react.js"></script>-->
<script src="~/Content/LikeButton.js" crossorigin="anonymous"></script>
<script>
// Find all DOM containers,and render Like buttons into them.
document.querySelectorAll(".test_container")
.forEach(domContainer => {
ReactDOM.render(React.createElement(LikeButton),domContainer);
});
</script>
</body>
</html>
LikeButton.js
'use strict';
class LikeButton extends React.Component {
constructor(props) {
super(props);
this.state = { liked: false };
}
render() {
if (this.state.liked) {
return 'You liked this.';
}
return React.createElement(
'button',{ onClick: () => this.setState({ liked: true }) },'Like'
);
}
}
``
解决方法
暂无找到可以解决该程序问题的有效方法,小编努力寻找整理中!
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