问题描述
是否可以按以下方式显示输入消息?
Enter First Fraction:_/_
Enter Second Fraction: _/_
_
在哪里输入空格?
使用下面的某种代码?
cout<<"Enter First Fraction: ";
cin>>N1>>"/">>D1;
cout<<"Enter Second Fraction: ";
cin>>N2>>"/">>D2;
OR
cout<<"Enter First Fraction: ";
cin>>N1>>/>>D1;
cout<<"Enter Second Fraction: ";
cin>>N2>>/>>D2;
解决方法
这是我的问题的解决方案,以防万一其他人面对它。 积分转到@ qPCR4vir
#include <iostream>
#include <conio.h>
#include <stdlib.h>
using namespace std;
main()
{ //This program encourages the user to perform a sum of two fractions.
int N1,D1,N2,D2,N,D;
char divide{};
system("cls");
cout<<"The Format is: 'A/B' & 'C/D'..\n\n";
cout<<"Enter First Fraction: ";
cin>>N1>>divide>>D1;
cout<<"Enter Second Fraction: ";
cin>>N2>>divide>>D2;
if (divide=='/')
{
N=(N1*D2)+(D1*N2); //Numerator
D=D1*D2; //Denominator
cout<<"Sum of Both Fractions is: "<<N<<"/"<<D;
}
else
{
system("cls");
cout<<"The Correct Format is: A/B & C/D\nWhere these alphabets are Integers..\n\n";
cout<<"Example: 4/5";
}
getch();
system("cls");
return(0);
}
这是仅指定“ cin
”语句格式的代码部分。
#include <iostream>
#include <stdlib.h>
#include <conio.h>
using namespace std;
int main()
{
char divide{}; //iota{};
int x{},y{};
cout<<"Enter Dividion of Two Numbers (A/B): ";
cin>>x>>divide>>y; //>> iota;
if (divide=='/') //&& iota=='i')
{
//x=(N1*D2)+(D1*N2); //Numerator
//y=D1*D2; //Denominator
cout<<"The Fractional Form is: "<<x<<"/"<<y;
}
else
{
system("cls");
cout<<"The Correct Format is: A/B & C/D\nWhere these alphabets are Integers..\n\n";
cout<<"Example: 4/5";
}
getch();
return 0;
}
注意:这是@ qPCR4vir的简化/修改后的解决方案,位于: Reading in a specific format with cin
,我在另一个堆栈问题中看到了此代码。
#include <iostream>
using namespace std;
int main()
{
char plus{},img{};
double x{},y{};
cin>> x >> plus >> y >> img;
if (plus!='+' || img!='i')
cout << "\nError: "<< "x=" << x <<",plus=" << plus <<",y=" << y <<",img=" << img;
else
cout << "\nComplex: " << x << plus << y << img;
return 0;
}
似乎要求用户在中间输入“ +”,然后输入“!”最后... 但是我尝试过,它仍然不起作用。