问题描述
我有一个Observable
,它结合了其他三个Observables
然后发出一个array
。从这个合并的array
中,我想获取最后10个对象。但是我想我改用最后十个arrays
。首先尝试使用compactMap
,但没有成功。它仍然以array
return Observable.combineLatest(breakfast,dessert,cookies) { $0 + $1 + $2 }
.compactMap { $0 }.takeLast(10)
.do(onNext: { [weak self] value in
self?.content.accept(value.compactMap {
NewRecipesCollectionViewCellviewmodel(recipe: $0)})
})
解决方法
通过这种方法,您可以一一获取元素:
let breakfast = Observable.just(["egg","milk"])
let dessert = Observable.just(["ice cream","chocolate"])
let cookies = Observable.just(["cookie1","cookie2"])
Observable.combineLatest(breakfast,dessert,cookies)
.map { $0 + $1 + $2 }
.do(onNext: { foods in
let lastTenFood = foods.suffix(10) // returns the last 10 elements from the array
for food in lastTenFood {
print("Food: \(food)")
}
})
.subscribe()
.disposed(by: disposeBag)