记录在一对多休眠关系中被替换

问题描述

我正在尝试在Hibernate黑白客户（一个）和订单（许多）的一对多关系中插入记录。但是在插入记录之后，数据库中的Customer表正在更新记录，但是 订单表记录将被覆盖。 也就是说，当我插入2个客户（每个客户有2个订单）时，customer表包含所有客户记录，但是订单表中的记录被覆盖。这是一个特殊的问题 请协助我解决问题。 预先感谢。

Customer.java

public class Customer{
private int customer_id;
private String name;
private long phone;
private String email;
private Set<Orders> orderSet;
//getters and setters
}

Orders.java

public class Orders implements Serializable
{
private int order_id;
private String orderDate;
private int cid;
}   

hibernate.cfg.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC"-//Hibernate/Hibernate Mapping DTD//EN""http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="entity.Customer">
<id name="customer_id" type="int">
    <column name="customer_id" not-null="true"/>
    <!-- Gets the max customer id from db and increment while inserting  --> 
    <generator class="increment"/>
</id>
<property name="name" type="java.lang.String" column="customer_name" length="70"/>
<property name="phone" type="long" column="customer_no"/>
<property name="email" type="java.lang.String" column="email" length="40" />
<set name="orderSet" cascade="all" inverse="true">
    <key column="customer_id"/>
    <one-to-many class="entity.Orders"/>
</set>  
</class>
</hibernate-mapping>

Customer.hbm.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC"-//Hibernate/Hibernate Mapping DTD//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="entity.Customer">
<id name="customer_id" type="int">
    <column name="customer_id" not-null="true"/>
    <!-- Gets the max customer id from db and increment while inserting  --> 
    <generator class="increment"/>
</id>
<property name="name" type="java.lang.String" column="customer_name" length="70"/>
<property name="phone" type="long" column="customer_no"/>
<property name="email" type="java.lang.String" column="email" length="40" />
<set name="orderSet" cascade="all" inverse="true">
    <key column="customer_id"/>
    <one-to-many class="entity.Orders"/>
</set>  
</class>
</hibernate-mapping>

Orders.hbm.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC"-//Hibernate/Hibernate Mapping DTD//EN""http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="entity.Orders">
    <id name="order_id" type="int">
         <column name="order_id"/>
        
    </id>
    <property name="orderDate" column="orderDate" type="java.lang.String" length="20"/>
    <property name="cid" column="customer_id" />
</class>
</hibernate-mapping>

Client.java

public class ClientImpl {

@SuppressWarnings("unused")
public static void main(String[] args) {
    
    BusinessImpl business=new BusinessImpl();
    Customer c= new Customer();
    c.setName("FirstCustomer");
    c.setPhone(1324567890l);
    c.setEmail("[e-mail]");
    HashSet<Orders> orderHSet=new HashSet<Orders>();
    Orders o1,o2;
    o1=new Orders(1,"C1O1_date");
    o2=new Orders(2,"C1O2_date");
    orderHSet.add(o1);
    orderHSet.add(o2);
    c.setOrderSet(orderHSet);
    business.insertCustomer(c);
    
    Customer c2= new Customer();
    c2.setName("SecondCustomer");
    c2.setPhone(1324567890l);
    c2.setEmail("[e-mail]");
    HashSet<Orders> orderHSet2=new HashSet<Orders>();
    Orders o21=new Orders(1,"C2O1_date");
    Orders o22=new Orders(2,"C2O2_date");
    orderHSet2.add(o21);
    orderHSet2.add(o22);
    c2.setOrderSet(orderHSet2);
    business.insertCustomer(c2);
}
}

BusinessImpl.java

public class BusinessImpl{

static DaoImpl dao=new DaoImpl();
public void insertCustomer(Customer c) {
    dao.createCustomerRecord(c);
}
}

DaoImpl.java

public class DaoImpl implements DaoInterface {
public void createCustomerRecord(Customer c) {
    Session session= UtilImplement.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    session.save(c);
    session.flush();
    session.clear();
}
}

解决方法

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