List-2> sum13编码蝙蝠问题：“ int”对象不可迭代

问题描述

我的代码有问题。问题是：

返回数组中数字的总和，对于空数组返回0。除非数字13非常不幸，所以它不计数，紧接在13之后的数字也不计数。 发件人：https://codingbat.com/prob/p167025

def sum13(nums):
  if not nums:
    return 0
  for x in nums:
    if x == 13:
      break
    return sum(x)
    if 13 not in nums:
      return sums(nums)

问题是我无法合并sum（x），并且每次尝试都会给出错误。 有人可以暗示为什么吗？

解决方法

错位的return是这里的许多问题之一，但它可能是解决逻辑问题的一个很好的开始。很难确定一旦解决将产生预期结果的单个问题。相反，存在一个普遍的问题，即实现与任务逻辑无关。

通常，您将问题分解为更简单的积木，如下所示：

def sum13(nums):
    # "Return the sum of the numbers in the array" 
    #  - let's iterate the array,increasing the sum
    res = 0
    previous_is_13 = False  # introduced later

    # "returning 0 for an empty array."
    # for loop will do nothing on empty arrays,as desired
    for i in nums:  
        # "Except the number 13 is very unlucky,so it does not count"
        # so,let's guard it with an if:
        if i == 13:
            # "numbers that come immediately after a 13 also do not count."
            # ok,let's set a flag to indicate that and clear it once we're past 13
            previous_is_13 = True
            continue

        if previous_is_13:
            previous_is_13 = False  # clear the flag and proceed to the next item
            continue
        res += i
    return res

有了基准解决方案后，请使其变得更好，例如使用迭代器：

def sum13(nums):
    return sum(value for i,value in enumerate(nums)
               if value!= 13 and (not i or nums[i-1] != 13))