问题描述
我遇到了这个挑战，要求根据提供的时间表打印出字符串。这是一个示例：
var restaurant = new Restaurant(
new openingHour(8,16),// Sunday
new openingHour(8,17),// Monday
new openingHour(8,// Tuesday
new openingHour(8,// Wednesday
new openingHour(8,// Thursday
new openingHour(8,// Friday
new openingHour(8,16) // Saturday
);
预期的输出结果 =“周日，周四-周六：8-16，周一-周三：8-17”
我所做的基本上是：
我已经尽力了，但是我知道我的代码根本不是高效的，而是凌乱的。我正在尝试提高我的C＃技能，请帮助。这是我的凌乱代码：
namespace Livit
{
using System;
using System.Collections.Generic;
using System.Linq;
public class Restaurant
{
public WeekCollection<openingHour> openingHours { get; private set; }
public Restaurant() {
// No opening hours available for restaurant
}
public Restaurant(openingHour monday,openingHour tuesday,openingHour wednesday,openingHour thursday,openingHour friday,openingHour saturday,openingHour sunday)
{
openingHours = new WeekCollection<openingHour>(monday,tuesday,wednesday,thursday,friday,saturday,sunday);
}
// THE EMPHASIS OF THE CHALLANGE IS THIS FUNCTION RIGHT HERE!!!
// Parse the date into desired format
public string DateParser(List<DayOfWeek> days,List<TimeSpan> openHours,List<TimeSpan> closeHours)
{
HashSet<string> availableRanges = new HashSet<string>();
List<string> timeRanges = new List<string>();
DayOfWeek current = DayOfWeek.Sunday;
string result = "";
for (int i = 0 ; i < days.Count; i++){
string timeRange = openHours[i].ToString().Substring(1,1)+'-'+closeHours[i].ToString().Substring(0,2);
availableRanges.Add(timeRange);
timeRanges.Add(timeRange);
}
List<string> arToList= availableRanges.ToList();
for (int i = 0 ; i < arToList.Count; i++)
{
for (int j = 0 ; j < timeRanges.Count; j++){
if(timeRanges[j] == arToList[i]){
// First Item
if(j==0 ){
result += days[j].ToString().Substring(0,3);
}
// Last Item
else if(j==timeRanges.Count-1){
char last = result.Last();
if(last != ' '){
result += " - ";
}
result += days[j].ToString().Substring(0,3);
}
// Everything in the middle
else{
if(days[j]-current > 1){
result += ",";
}
if(timeRanges[j] != timeRanges[j-1] ){
result += days[j].ToString().Substring(0,3);
} else if (timeRanges[j] == timeRanges[j-1]){
char last = result.Last();
if(last != ' '){
result += " - ";
}
if(timeRanges[j] != timeRanges[j+1]){
result += days[j].ToString().Substring(0,3);
}
}
}
current = days[j];
}
}
result += ": " + arToList[i];
if(i!=arToList.Count-1){
result += ",";
}
}
Console.WriteLine(result);
return result;
}
public string GetopeningHours()
{
// Declare List for each attribute
List<DayOfWeek> days = new List<DayOfWeek>();
List<TimeSpan> openHours = new List<TimeSpan>();
List<TimeSpan> closeHours = new List<TimeSpan>();
// Call the opening and closing hours from each day and Feed into new array
foreach (DayOfWeek day in Enum.GetValues(typeof(DayOfWeek)).OfType<DayOfWeek>().ToList()) {
TimeSpan openHour = openingHours.Get(day).openingTime;
TimeSpan closeHour = openingHours.Get(day).ClosingTime;
days.Add(day);
openHours.Add(openHour);
closeHours.Add(closeHour);
}
return DateParser(days,openHours,closeHours);
throw new NotImplementedException();
}
}
public class openingHour
{
public TimeSpan openingTime { get; private set; }
public TimeSpan ClosingTime { get; private set; }
public openingHour(TimeSpan openingTime,TimeSpan closingTime)
{
openingTime = openingTime;
ClosingTime = closingTime;
}
public openingHour(int openingHour,int closingHour)
{
openingTime = TimeSpan.FromHours(openingHour);
ClosingTime = TimeSpan.FromHours(closingHour);
}
}
public class WeekCollection<T>
{
private Dictionary<DayOfWeek,T> _collection;
public WeekCollection(T sunday,T monday,T tuesday,T wednesday,T thursday,T friday,T saturday)
{
_collection = new Dictionary<DayOfWeek,T>();
_collection.Add(DayOfWeek.Sunday,sunday);
_collection.Add(DayOfWeek.Monday,monday);
_collection.Add(DayOfWeek.Tuesday,tuesday);
_collection.Add(DayOfWeek.Wednesday,wednesday);
_collection.Add(DayOfWeek.Thursday,thursday);
_collection.Add(DayOfWeek.Friday,friday);
_collection.Add(DayOfWeek.Saturday,saturday);
}
public T Get(DayOfWeek dayOfWeek)
{
return _collection[dayOfWeek];
}
}
}
目前，我仍在尝试寻找一种更好的方法来应对这一挑战。任何帮助都会得到应用。
P.S。我强调了发生串联的部分，这部分基本上是整个挑战的重点
解决方法
暂无找到可以解决该程序问题的有效方法，小编努力寻找整理中！
如果你已经找到好的解决方法，欢迎将解决方案带上本链接一起发送给小编。
小编邮箱:dio#foxmail.com (将#修改为@）