问题描述
上下文
这是我几天前问的that question的后续问题,尽管并非必须事先阅读。
我有一个API端点/common
,它以这种形式返回JSON数据:
{
"data":
{
"players": [
{
"id": 1,"name": "John Doe"
},{
"id": 15,"name": "Jessica Thump"
}],"games": [
{
"name": "Tic Tac Toe","playerId1": 15,"playerId2": 1
}]
}
}
在其他代码段中,假定此响应作为String
存储在变量rawApiResponse
中。
我的目的是根据Swift struct
的要求对其进行解码:
struct Player: Decodable {
var id: Int
var name: String?
}
struct Game: Decodable {
var name: String
var player1: Player
var player2: Player
enum CodingKeys: String,CodingKey {
case name
case player1 = "playerId1"
case player2 = "playerId2"
}
}
多亏了我原来的问题,我现在可以成功解码Player
和Game
了,但是只有当我使用的响应String
是内部数组{{ 1}}:
e.g.
问题
如何从let playersResponse = """
[
{
"id": 1,"name": "John Doe"
},{
"id": 15,"name": "Jessica Thump"
}
]
"""
let players = try! JSONDecoder().decode([Player].self,from: playersResponse.data(using: .utf8)!)
的API响应中仅提取JSON "players"
数组,以便以后可以将其馈送到/common
的JSON解码器中?
请注意,我不能使用(或至少是我认为的)制作超级Player
的“常规” Decodable
方法,因为我需要Struct
在players
之前解码(这是原始问题的主题)。因此,这不起作用:
games
到目前为止我尝试过的事情
我调查了how to convert a JSON string to a dictionary,但这只是部分帮助了
struct ApiResponse: Decodable {
let data: ApiData
}
struct ApiData: Decodable {
let players: [Player]
let games: [Game]
}
let data = try! JSONDecoder().decode(ApiResponse.self,from: rawApiResponse.data(using: .utf8)!)
如果我转储let json = try JSONSerialization.jsonObject(with: rawApiResponse.data(using: .utf8)!,options: .mutableContainers) as? [String:AnyObject]
let playersRaw = json!["data"]!["players"]!!
,它看起来像我想要的,但是我不知道如何将其强制转换为playersRaw
并以{{1} }是Data
。
我觉得我没有按照应有的方式做事,所以如果您对一般问题有更“迅速”的解决方案(而不是专门针对如何提取子集) JSON数据),那就更好了!
解决方法
您可以通过在ApiData
中自己实现解码并在players
数组中搜索每个播放器ID来实现这一目标:
struct ApiResponse: Decodable {
let data: ApiData
}
struct ApiData: Decodable {
let players: [Player]
var games: [Game]
enum CodingKeys: String,CodingKey {
case players
case games
}
enum GameCodingKeys: String,CodingKey {
case name
case playerId1
case playerId2
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
players = try container.decode([Player].self,forKey: .players)
var gamesContainer = try container.nestedUnkeyedContainer(forKey: .games)
games = []
while !gamesContainer.isAtEnd {
let gameContainer = try gamesContainer.nestedContainer(keyedBy: GameCodingKeys.self)
let playerId1 = try gameContainer.decode(Int.self,forKey: .playerId1)
let playerId2 = try gameContainer.decode(Int.self,forKey: .playerId2)
guard
let player1 = players.first(where: { $0.id == playerId1 }),let player2 = players.first(where: { $0.id == playerId2 })
else { continue }
let game = Game(
name: try gameContainer.decode(String.self,forKey: .name),player1: player1,player2: player2
)
games.append(game)
}
}
}
struct Player: Decodable {
var id: Int
var name: String?
}
struct Game: Decodable {
var name: String
var player1: Player
var player2: Player
}
这有点丑陋,但最终您可以像这样使用它:
let decoder = JSONDecoder()
do {
let response = try decoder.decode(ApiResponse.self,from: rawApiResponse.data(using: .utf8)!)
let games = response.data.games
print(games)
} catch {
print(error)
}
,
您只需要提供一个根结构并获取其数据播放器即可。无需解码不需要的值:
struct ApiResponse: Decodable {
let data: ApiData
}
struct ApiData: Decodable {
let players: [Player]
let games: [Game]
}
struct Player: Codable {
let id: Int
let name: String
}
struct Game: Decodable {
var name: String
var player1: Int
var player2: Int
enum CodingKeys: String,CodingKey {
case name,player1 = "playerId1",player2 = "playerId2"
}
}
let common = """
{
"data":
{
"players": [
{
"id": 1,"name": "John Doe"
},{
"id": 15,"name": "Jessica Thump"
}],"games": [
{
"name": "Tic Tac Toe","playerId1": 15,"playerId2": 1
}]
}
}
"""
do {
let players = try JSONDecoder().decode(ApiResponse.self,from: Data(common.utf8)).data.players
print(players) // [__lldb_expr_48.Player(id: 1,name: "John Doe"),__lldb_expr_48.Player(id: 15,name: "Jessica Thump")]
let games = try JSONDecoder().decode(ApiResponse.self,from: Data(common.utf8)).data.games
print(games) // [__lldb_expr_52.Game(name: "Tic Tac Toe",player1: 15,player2: 1)]
// or get the common data
let commonData = try JSONDecoder().decode(ApiResponse.self,from: Data(common.utf8)).data
print(commonData.players)
print(commonData.games)
} catch {
print(error)
}