您如何判断用户是启动onTaskRemoved还是系统启动了？

问题描述

我的目标是使用户能够将某个应用程序轻扫开并关闭前台服务。我通过重写onTaskRemoved来做到这一点。这可以按预期工作，并且我从该方法关闭了我的服务，但是现在存在系统使用onTaskRemoved关闭前台服务的问题。

忘记我使用的设置，但是我的应用在待机应用中被列为免税项目。

如何阻止系统关闭前台服务？

我会按照开发人员指南的内容进行操作。

        Intent intentServiceMain = new Intent(ActivityMain.this,ServiceMain.class);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            startForegroundService(intentServiceMain);
        } else {
            startService(intentServiceMain);
        }

    @Override
    public int onStartCommand(Intent intent,int flags,int startId) {
            Toast.makeText(getApplicationContext(),"Service starting",Toast.LENGTH_SHORT).show();
            setUpNotificationBuilder();
            notification = notificationCompatBuilder.build();
            startForeground(NOTIFICATION_CHANNEL_ID.hashCode(),notification);
            return START_STICKY;
    }

    private void setUpNotificationBuilder() {
        notificationCompatBuilder = new NotificationCompat.Builder(
                getApplicationContext(),NOTIFICATION_CHANNEL_ID)
                .setSmallIcon(R.drawable.music_note_black_48dp)
                .setContentTitle(NOTIFICATION_CHANNEL_ID)
                .setPriority(NotificationCompat.PRIORITY_LOW)
                .setVisibility(NotificationCompat.VISIBILITY_PUBLIC)
                .setStyle(new NotificationCompat.DecoratedCustomViewStyle());
        remoteViewsNotificationLayout =
                new RemoteViews(getPackageName(),R.layout.pane_notification);
        notificationCompatBuilder.setCustomContentView(remoteViewsNotificationLayout);
        Intent notificationIntent = new Intent(getApplicationContext(),ActivityMain.class);
        PendingIntent pendingIntent = PendingIntent.getActivity(
                getApplicationContext(),notificationIntent,0);
        notificationCompatBuilder.setContentIntent(pendingIntent);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            int importance = notificationmanager.IMPORTANCE_LOW;
            NotificationChannel channel = new NotificationChannel(NOTIFICATION_CHANNEL_ID,NOTIFICATION_CHANNEL_ID,importance);
            String description = "Service";
            channel.setDescription(description);
            notificationmanager notificationmanager = getSystemService(notificationmanager.class);
            notificationmanager.createNotificationChannel(channel);
        }
    }

解决方法

暂无找到可以解决该程序问题的有效方法，小编努力寻找整理中！

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