问题描述
我一直困扰着这个小问题:如何在范围函数中使用用户输入来“停止”,然后将字符串(在这种情况下为字母)镜像回去,而无需两次输入。
现在,代码只能包含一个数字,但是最好输入一个字母,然后将其转换为正确的数字,以便将其放置在字母中。并将其用于范围! 但是我尝试了转弯,但结果却没有令人满意的结果。
感谢您的时间和耐心!
def front_aplhabet():
alphabet = ''
for letter in range(0,human):
alphabet += chr(ord("a") + letter)
return alphabet
# function to mirror front_aplhabet output
def back_alphabet(input):
return input[::-1]
human = int((input("Please enter a letter: "))
palidrome_2 = front_aplhabet() + back_alphabet(front_aplhabet())
print(palidrome_2)
输出示例:
Please enter a letter: 5
abcdeedcba
目标是获得以下成就:
Please enter a letter: "e"
abcdefgfedcba
请务必批判我在这里学习!
我也尝试过
def front_aplhabet():
alphabet = ''
for letter in range(0,int(goat)):
alphabet += chr(ord("a") + letter)
return alphabet
# function to mirror front_aplhabet output
def back_alphabet(input):
return input[::-1]
human = (input("Please enter a letter: "))
goat = ord(human)
palidrome_2 = front_aplhabet() + back_alphabet(front_aplhabet())
print(palidrome_2)
输出:
Please enter a letter: 5
abcdefghijklmnopqrstuvwxyz{|}~~}|{zyxwvutsrqponmlkjihgfedcba
目标是获得以下成就:
Please enter a letter: "g"
abcdefgfedcba
解决方法
您似乎想问用户一个字母,然后列出前几个字母以及镜子。
尝试此代码
def front_alphabet(human):
alphabet = ''
for letter in range(0,human):
alphabet += chr(ord("a") + letter)
return alphabet
# function to mirror front_aplhabet output
def back_alphabet(input):
return input[::-1]
human = ord(input("Please enter a letter: ")) - 97 # convert lowercase letter to ascii
palidrome_2 = front_alphabet(human) + chr(human+97) + back_alphabet(front_alphabet(human))
print(palidrome_2)
输出
Please enter a letter: g
abcdefgfedcba