问题描述
guess_two_numbers.c
#include <stdio.h>
void print_error()
{
printf("\n Oooops,incorrect guess!\n");
exit(1);
}
int main()
{
int num1,num2;
printf("\n Guess my two secret numbers: ");
scanf("%d %d",&num1,&num2);
if(num1 > 11)
print_error();
if(num2 != num1 + 2)
print_error();
printf("\nCongratulations,you've found my two secret numbers!\n");
return 0;
}
0x08048462 <+0>: lea ecx,[esp+0x4]
0x08048466 <+4>: and esp,0xfffffff0
0x08048469 <+7>: push DWORD PTR [ecx-0x4]
0x0804846c <+10>: push ebp
0x0804846d <+11>: mov ebp,esp
0x0804846f <+13>: push ecx
0x08048470 <+14>: sub esp,0x24
0x08048473 <+17>: mov DWORD PTR [esp],0x80485c0
0x0804847a <+24>: call 0x8048360 <printf@plt>
0x0804847f <+29>: lea eax,[ebp-0xc]
0x08048482 <+32>: mov DWORD PTR [esp+0x8],eax
0x08048486 <+36>: lea eax,[ebp-0x8]
0x08048489 <+39>: mov DWORD PTR [esp+0x4],eax
0x0804848d <+43>: mov DWORD PTR [esp],0x80485e0
0x08048494 <+50>: call 0x8048350 <scanf@plt>
0x08048499 <+55>: mov eax,DWORD PTR [ebp-0x8]
0x0804849c <+58>: cmp eax,0xb
0x0804849f <+61>: jle 0x80484a6 <main+68>
0x080484a1 <+63>: call 0x8048444 <print_error>
0x080484a6 <+68>: mov eax,DWORD PTR [ebp-0x8]
0x080484a9 <+71>: lea edx,[eax+0x2]
0x080484ac <+74>: mov eax,DWORD PTR [ebp-0xc]
0x080484af <+77>: cmp edx,eax
0x080484b1 <+79>: je 0x80484b8 <main+86>
0x080484b3 <+81>: call 0x8048444 <print_error>
0x080484b8 <+86>: mov DWORD PTR [esp],0x80485e8
0x080484bf <+93>: call 0x8048370 <puts@plt>
0x080484c4 <+98>: mov eax,0x0
0x080484c9 <+103>: add esp,0x24
0x080484cc <+106>: pop ecx
0x080484cd <+107>: pop ebp
0x080484ce <+108>: lea esp,[ecx-0x4]
0x080484d1 <+111>: ret
我被问到的问题是确定汇编代码中哪些行符合密码要求(第一个密码为的行是一行,因为它将eax与0xb(十六进制为11)进行比较。我还说过也是包含它的一行,因为它在eax上添加+2以检查第二个要求。这足够了还是我应该添加更多细节?
解决方法
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