问题描述
下面的代码完成了它的工作:它为我提供了每个类别的前10个结果。
SELECT *
FROM (
SELECT *,RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 10
现在,我想添加条件,以便结果的数量可以根据条件而有所不同。例子:如果“ note” = 1,那么我想保留1个结果,否则取3。
我尝试过使用CASE WHEN语句在下面看到的内容,但是您可能希望它不起作用。返回错误:
1-在“ CASE”附近:语法错误
SELECT *
CASE WHEN "note" = 1 THEN
SELECT *
FROM (
SELECT *,RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 1
ELSE
SELECT *
FROM (
SELECT *,RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 3
END
您对如何进行这项工作有任何想法吗?我对sql的了解非常有限。当我在QGIS环境中工作时,代码必须与sqlite / SpatiaLite兼容。谢谢。
解决方法
您可以在外部查询的WHERE
子句中使用布尔逻辑:
SELECT *
FROM (
SELECT t.*,RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing" t
) AS x
WHERE ("note" = 1 and rnk = 1) OR rnk <= 3