问题描述
“进度”数据库中的地址字段显然是多行。因此，如果我做一些简单的事情，例如：
for each customer where customer-number = "123" no-lock.
display customer-number
customer-name
customer-address.
我得到以下结果：
123 John Smith 123 Easy St.
c/o Jane Smith
Apartment C12
我想要以下结果：
123 John Smith 123 Easy St. c/o Jane Smith Apartment C12
我尝试了Entry-但如果元素不存在，则会出现错误。我正在尝试导出为CSV，并希望每一行都是另一列，如果某列不存在，则为空白。
任何帮助将不胜感激！
解决方法
如果定界符是换行符，则应执行以下操作：
define variable n as integer no-undo.
define variable i as integer no-undo.
define variable address as character no-undo.
output to value( "customer.csv").
for each customer no-lock:
address = "".
n = num-entries( customer-address,"~n" ).
do i = 1 to n:
address = address + entry( i,customer-address,"~n" ) + " ".
end.
export delimiter "," customer-number customer-name trim( address ).
end.
output close.
或者，如果您只需要在客户地址字段中更改定界符：
output to value( "customer.csv").
for each customer no-lock:
export delimiter "," customer-number customer-name replace( customer-address,"~n","," ).
end.
output close.
（实际上，我的原始代码实际上只是将〜n替换为空格，因此您也可以这样做...）