如何在声明数组php中添加if函数

问题描述

你好，我在这里遇到问题，我想像这样在PHP的数组声明中创建一个if语句

foreach($data as $d){
$temparray = [
                if($d['STAT'] =='STUND'){
                    'stat_acc' => $stat_stund_acc,'stat_blok' => $stat_stund_blok
                 }else{
                    'stat_acc' => $stat_acc,'stat_blok' => $stat_blok
                 }
                 'other_data1' => $other_data1
                 'other_data2' => $other_data2

            ];
}

但是在我的vscode中有一个警告错误

解决方法

为什么不喜欢这个？

$temparray = [];
if($d['STAT'] =='STUND'){
    $temparray = [
        'stat_acc' => $stat_stund_acc,'stat_blok' => $stat_stund_blok,'other_data1' => $other_data1,'other_data2' => $other_data2
    ];
}
else{
    $temparray = [
        'stat_acc' => $stat_acc,'stat_blok' => $stat_blok,'other_data2' => $other_data2
    ];
}

,

您可以按照@rafalrozek所说的用一般的if来保护整个事情，或者也可以只保护自己想要的东西：

foreach ($data as $d) {
    $temparray = [
        'other_data1' => $other_data1,'other_data2' => $other_data2,];

    if ($d['STAT'] == 'STUND') {
        $temparray['stat_acc'] = $stat_stund_acc;
        $temparray['stat_blok'] = $stat_stund_blok;
    } else {
        $temparray['stat_acc'] = $stat_acc;
        $temparray['stat_blok'] = $stat_blok;
    }
}

此外，只要条件检查不太昂贵，就可以使用三元：

foreach ($data as $d) {
    $temparray = [
        'stat_acc' => $d['STAT'] == 'STUND' ? $stat_stund_acc : $stat_acc,'stat_blok' => $d['STAT'] == 'STUND' ? $stat_stund_blok : $stat_blok,];
}