问题描述
我有一组包含日志列表的帐户
如果日志的“ loggedAt”字段早于5天,则我需要删除帐户的“日志”列表中的每个日志,而不会留下孤立的日志或破坏“日志”列表的引用。
如何使用AQL或arangosh命令实现这一目标?
类似这样的东西
nf.loc[:,'priorBDay'] = np.busday_offset(nf.curr_date.values.astype('M8[M]') + np.timedelta64(-1,'M'),-1,roll='forward')
帐户凭证示例
datetime64[ns,UTC]
Account.class
FOR a IN account
FOR l IN log
FILTER l._id IN a.logs
FILTER DATE_DIFF(l.loggedAt,DATE_Now(),'days',false) > 5
UPDATE a WITH { logs: REMOVE_VALUE( a.logs,l ) } IN account
REMOVE { _key: l._key } IN log
日志文档示例
_id:account/1085466856
_rev:_bIYHFNu---
_key:1085466856
{
"_class": "com.app.Account","logs": [
"log/1085468455","log/1085468456","log/1085468457"
]
}
Log.class
@Data
@Document("account")
public class Account implements Serializable {
private static final long serialVersionUID = -1615384653229054932L;
@Id
private String id;
@Ref(lazy = false)
private Collection<Log> logs;
}
解决方法
您可以通过2个AQL查询来做到这一点:
- 先删除日志:
LET fiveDaysAgo = DATE_SUBTRACT(DATE_NOW(),5,'days')
FOR rec IN log
FILTER DATE_DIFF(rec.loggedAt,fiveDaysAgo,'days') >= 0
REMOVE rec IN log
- 下一步清理帐户:
FOR acc IN account
LET validLogs = (
FOR accLog IN acc.logs
FOR rec IN log
FILTER accLog == rec._id
RETURN rec._id
)
FILTER LENGTH(acc.logs) != LENGTH(validLogs)
UPDATE acc WITH {logs: validLogs} IN account
如果需要,可以将以上查询合并为一个查询:
LET fiveDaysAgo = DATE_SUBTRACT(DATE_NOW(),'days')
FOR acc IN account
LET invalidLogs = (
FOR accLog IN acc.logs
FOR rec IN log
FILTER accLog == rec._id
FILTER DATE_DIFF(rec.loggedAt,'days') >= 0
REMOVE rec IN log
RETURN OLD._id
)
FILTER LENGTH(invalidLogs) > 0
UPDATE acc WITH {logs: OUTERSECTION(acc.logs,invalidLogs)} IN account
但是,如果您在log
集合中有僵尸记录(与account
记录没有任何关联的记录),上面的查询将使它们保持不变。