为单个类创建多个 operator<<() 定义

问题描述

所以基本上这就是我想做的：

void someMethod() {
    StreamClass streamClass{};

    streamClass << "Something" << "\n"; //do something
    streamClass.doA << "Something" << "\n"; //do another thing
    streamClass.doB << "Something" << "\n"; //do something else

    //If the first one is impossible,what about this?
    streamClass << "Something" << "\n"; //do something
    streamClass::doA << "Something" << "\n"; //do another thing
    streamClass::doB << "Something" << "\n"; //do something else

    //Or this?
    streamClass<enumA> << "Something" << "\n"; //do something
    streamClass<enumB> << "Something" << "\n"; //do another thing
    streamClass<enumC> << "Something" << "\n"; //do something else
}

头文件：

class StreamClass {
public:
    StreamClass(); //Init class
    //... and many other things
    template<typename T>
    StreamClass& operator<<(T t) {
        //... do something that uses data and t
    }
    //And do something here?
protected:
    Data data; //some data owned by this object
};

那么，有没有办法做这样的事情？以及如何以最快的方式做到这一点？

解决方法

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