问题描述
我想将数组转换为重新组合同一国家/地区的所有城市。 我有一个对象数组
filesize("audio/$file")
我想要这个:
locations = [
{
cities: ["Paris"]
country: "France"
},{
cities: ["Marseille"]
country: "France"
},{
cities: ["Kiev"]
country: "Ukraine"
},{
cities: ["Odessa"]
country: "Ukraine"
}
...
所以,我的想法是:
locations = [
{
cities: ["Paris","Marseille"]
country: "France"
},{
cities: ["Kiev,Odessa"]
country: "Ukraine"
},...
对于第一对相等的国家,curr.cities[0] 被推送到 prev.cities,但不是下一次迭代: 类型错误:无法读取未定义的属性“国家/地区”
[![console.log(locations) - TypeError: 无法读取未定义的属性 'country'][1]][1]
解决方法
使用reduce
时,需要返回prev
以供下次迭代使用,并且初始化为{}
。此外,您需要注意每个国家/地区的初始添加,其中应存储具有 cities
数组的对象:
const locations = [
{ country: "France",cities: ['city1','city2'] },{ country: "France",cities: ['city3','city4'] },{ country: "Ukraine",cities: ['city5'] },cities: ['city6'] }
];
const res = Object.values(locations.reduce((prev,curr) => {
const { country,cities = [] } = curr;
const [city] = cities;
if (prev[country] && city) {
prev[country].cities.push(city);
} else {
prev[country] = { country,cities: city ? [city] : [] };
}
return prev;
},{}));
console.log(res);
您可以创建一个以国家/地区为键的 Map,并使用一个初始为空的数组作为相应的值。然后填充这些数组,最后从该 Map 中提取条目。这具有线性时间复杂度:
let locations = [{cities: ["Paris"],country: "France"},{cities: ["Marseille"],{cities: ["Kiev"],country: "Ukraine"},{cities: ["Odesa"],country: "Ukraine"}];
let map = new Map(locations.map(({country}) => [country,{country,cities: []}]));
for (let loc of locations) map.get(loc.country).cities.push(...loc.cities);
let res = Array.from(map.values());
console.log(res);
我认为要获得所需的输出格式,您可以执行以下操作:
locations = [
{ cities: ["Paris"],country: "France" },{ cities: ["Marseille"],{ cities: ["Kiev"],country: "Ukraine" },{ cities: ["Odesa"],country: "Ukraine" }
];
var grouped = Object.entries(
locations.reduce((a,cities}) => ({
...a,[country]: [...(a[country] || []),...cities]
}),{})
).map(([country,cities]) => ({ country: country,cities: cities }),[]);
console.log(grouped);