问题描述
在 playwright-python 中,我知道我可以使用 elementHandle
获得 querySelector()
。
示例(同步):
from playwright import sync_playwright
with sync_playwright() as p:
for browser_type in [p.chromium,p.firefox,p.webkit]:
browser = browser_type.launch()
page = browser.newPage()
page.goto('https://duckduckgo.com/')
element = page.querySelector('input[id=\"search_form_input_homepage\"]')
如何根据此 elementHandle
获取与 this 相关的 an 元素? IE。父母、祖父母、兄弟姐妹、孩子处理?
解决方法
使用 querySelector()
/ querySelectorAll
与
XPath (XML Path Language) 允许您检索 elementHandle
(分别是句柄的集合)。一般来说,XPath 可用于浏览 XML 文档中的元素和属性。
from playwright import sync_playwright
with sync_playwright() as p:
for browser_type in [p.chromium,p.firefox,p.webkit]:
browser = browser_type.launch(headless=False)
page = browser.newPage()
page.goto('https://duckduckgo.com/')
element = page.querySelector('input[id=\"search_form_input_homepage\"]')
parent = element.querySelector('xpath=..')
grandparent = element.querySelector('xpath=../..')
siblings = element.querySelectorAll('xpath=following-sibling::*')
children = element.querySelectorAll('xpath=child::*')
browser.close()