TMDb API - 按流派 ID 过滤

问题描述

我想按类型 ID 过滤电影，然后将它们显示在与其匹配的页面中。

我通过使用获得了流派 ID：

this.actRoute.snapshot.params['id']

路由

{path: 'genre/:id',component:GenrePageComponent}

服务

  getAllMovies(page){
    return this.http.get(`https://api.themoviedb.org/3/movie/popular?api_key=X&language=en-US&page=${page}`)
  }

响应示例：

 "results": [
        {
            "adult": false,"backdrop_path": "/cjaOSjsjV6cl3uXdJqimktT880L.jpg","genre_ids": [
                12,14,10751,16
            ],"id": 529203,"original_language": "en","original_title": "The Croods: A New Age","overview": "After leaving their cave,the Croods encounter their biggest threat since leaving: another family called the Bettermans,who claim and show to be better and evolved. Grug grows suspicIoUs of the Betterman parents,Phil and Hope,as they secretly plan to break up his daughter Eep with her loving boyfriend Guy to ensure that their daughter Dawn has a loving and smart partner to protect her.","popularity": 3189.651,"poster_path": "/tK1zy5BsCt1J4OzoDicXmr0UTFH.jpg","release_date": "2020-11-25","title": "The Croods: A New Age","video": false,"Vote_average": 8.1,"Vote_count": 509
        },

TS 文件

  getAllMovies(){
    for(let i = 1; i<=500; i++){
      this.movies.push(this.moviesService.getAllMovies(i))
    }
    forkJoin(this.movies).subscribe((data:any[])=>{
      this.allMovies = data.flat(1)
      console.log("All Movies:",this.allMovies)
    }) 
  }
}

所以“this.allmovies”包含所有电影：

我尝试过类似的操作，但只收到一个空数组：

  sortCat(){
    for(let i = 1; i<=500; i++){
      this.movies.push(this.moviesService.getAllMovies(i))
    }
    forkJoin(this.movies).pipe(
      map((movies:Object[])=>movies.filter(movie=>movie.results.genre_ids == this.actRoute.snapshot.params['id']))
    )
    .subscribe((data:any[])=>{
      this.test = data
      console.log("TEST:",this.test)
    })
    // console.log("All Movies2:",this.allMovies.results)
  }

如何将 params['id'] 与电影的“genre_ids”匹配？

非常感谢！

解决方法

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angular observable themoviedb-api