问题描述
为什么 IBM 自然语言分类器返回 DecodeError ? 我尝试对集合进行分类,但现在它返回错误。 一周前,它运行完美
我的代码
classes_values = []
for i in range(0,len(materiasg),10):
classes = natural_language_classifier.classify_collection(
classifier_id,[{"text":materia} for materia in materiasg[i:(i+10 if i+10 < len(materiasg ) else len(materiasg))]]).get_result()
c = [sorted([[dicionario_classe["class_name"],dicionario_classe["confidence"]] for dicionario_classe in i["classes"]],key=lambda x: x[0]) for i in classes["collection"]]
classes_values += c
classes_values = np.array(classes_values)
---------------------------------------------------------------------------
DecodeError Traceback (most recent call last)
<ipython-input-80-d2b25928198b> in <module>()
3 classes = natural_language_classifier.classify_collection(
4 classifier_id,----> 5 [{"text":materia} for materia in materiasg[i:(i+10 if i+10 < len(materiasg ) else len(materiasg))]]).get_result()
6 c = [sorted([[dicionario_classe["class_name"],key=lambda x: x[0]) for i in classes["collection"]]
7 classes_values += c
7 frames
/usr/local/lib/python3.6/dist-packages/jwt/api_jwt.py in decode_complete(self,jwt,key,algorithms,options,**kwargs)
78 if options["verify_signature"] and not algorithms:
79 raise DecodeError(
---> 80 'It is required that you pass in a value for the "algorithms" argument when calling decode().'
81 )
82
DecodeError: It is required that you pass in a value for the "algorithms" argument when calling decode().
解决方法
由于最新版本的 PyJWT (2.0.0),您可能会遇到此问题。 尝试使用“pip install PyJWT==1.7.1”返回到以前的版本,看看您的项目是否有效。