在 python 中练习循环时遇到问题

问题描述

import time
import random
import math

start = 1
stop = 10

for i in range(start,stop):
    time.sleep(1)
    print("\ni = {}".format(i),end = "")
    count = 3 + random.randint(1,5)
    print(",count = {}".format(count))
    nums = []
    while len(nums) < count:
        for j in range(count):
            time.sleep(0.3)
            try:
                num = random.randint(-10,100)
                log = round(math.log(num),1)
            except:
                time.sleep(2)
                print("\nagain")
                break
            nums.append(log)
            print("\rnums = {}".format(nums),end = "")

我想要做的是为每次迭代 count 提供一个随机整数 i，然后使用 while 循环将 num 的日志附加到 {{1 }} 直到 nums 的长度等于 nums。这里 count 是 -10 到 100 之间的随机整数，如果 num 为 0 或以下，我想从 num 的最开始重新开始循环，即for i in range(start,stop):，以便我可以指定新的 time.sleep(1) 并生成新的 count。

所以我执行了上面的代码，它从nums的开头再次开始循环。

例如，我的预期是这样的

while len(nums) < count:

等等

我得到的是

i = 1,count = 7
nums = [4.2,4.4,2.9,4.4]
again
i = 1,count = 5
nums = [3.5,3.6,4.2]
again
i = 1,count = 6
nums = [2.0,3.2,3.5,4.2,4.5]
i = 2,count = 5
nums = [4.5,4.1,4.0,3.9,3.8]
i = 3,count = 6
nums = [4.3,3.8]
again
i = 3,count = 5
nums = [3.0,3.4,4.6,3.1]

等等

解决方法

将其全部放入一个函数中，并在 num 小于或等于 0 时再次调用它

import time
import random
import math

start = 1
stop = 10

def whatever():
    for i in range(start,stop):
        time.sleep(1)
        print("\ni = {}".format(i),end = "")
        count = 3 + random.randint(1,5)
        print(",count = {}".format(count))
        nums = []
        while len(nums) < count:
            for j in range(count):
                time.sleep(0.3)
                num = random.randint(-10,100)

                if num <= 0:
                    time.sleep(2)
                    print("\nagain")
                    whatever()
                else:
                    log = round(math.log(num),1)
                    nums.append(log)

                print("\rnums = {}".format(nums),end = "")

whatever()

如果 num 小于或等于 0，这里将再次开始循环

if num <= 0:
    time.sleep(2)
    print("\nagain")
    whatever()

输出：

i = 1,count = 8
nums = [4.2,2.9,3.8,2.1,4.0,4.1,4.4]
i = 2,count = 5
nums = [3.4,3.2,3.6,4.5]
again

i = 1,count = 8
nums = [3.5,4.2,4.3,3.9,3.5,1.1,3.2]
i = 2,count = 7

again

i = 1,count = 8
nums = [2.4,3.0,4.5,3.6]