问题描述
我有以下 JAXB 注释类:
@Data
@XmlAccessorType(XmlAccesstype.NONE)
@XmlRootElement(name="Channels",namespace="http://abc.channeltypes")
public class Channels {
@XmlElement(name = "Channel",required = true)
private @Valid @NotNull List<Channel> channels;
}
@Data
@Getter
@XmlRootElement(name = "Channel")
@XmlAccessorType(XmlAccesstype.NONE)
public class Channel {
@XmlElement(name = "ChannelId")
private Integer channelId;
@XmlElement(name = "Name",required = true)
private @NotEmpty String name;
@XmlElement(name = "Type",required = true)
private @NotEmpty String type;
当我尝试反序列化输入时,出现以下错误:
无法识别的字段“Channel”(类 a.request.Channels),未标记为可忽略(一个已知属性:“channels”]) 在 [来源: (StringReader);行:1,列:136](通过引用链:a.request.Channels["Channel"])
我正在尝试为 post 请求创建一个模拟服务器,所以当我收到 JAXB xml 格式的请求时, 我尝试使用映射器读取请求正文并将其映射到对象。
mockServer.when(
request()
.withPath("/[a-z]/[a-z]+")
.withMethod("POST")
.withHeader(
new Header("Content-Type","application/xml"))
)
.respond(
httpRequest -> {
ChannelRef channelRef = new ChannelRef();
String body = httpRequest.getBodyAsstring();
Channels channelsRequestBody =new XmlMapper().readValue(body,Channels.class);
channelsRequestBody.getChannels().forEach(channel -> {
Channel createdChannel = createChannel(channel);
channelRef.setChannelId(createdChannel.getChannelId());
channelRef.setExternalId(createdChannel.getExternalId());
});
Response response = getokResponse(channelRef);
return response()
.withBody(
new ObjectMapper()
.writeValueAsstring(
response
)
).withStatusCode(201)
.withContentType(MediaType.APPLICATION_JSON);
}
);
private static Response getokResponse(ChannelRef channelRef) {
Response response = new Response();
response.setResultCode(HttpStatus.OK.name());
response.setSystemTime(System.currentTimeMillis());
response.setResultObj(channelRef);
return response;
}
有人可以解释我如何解决它。 我尝试了很多替代方案,但似乎没有奏效。
解决方法
我找到了解决方案。
要传递 XML 内容,您需要将内容包装在 Reader 中,然后对其进行解组:
JAXBContext jaxbContext = JAXBContext.newInstance(Channels.class); 解组器 unmarshaller = jaxbContext.createUnmarshaller();
StringReader reader = new StringReader(body); 通道 a= (Channels) unmarshaller.unmarshal(reader);