如何设置 SOAPMessage 边界?

问题描述

我正在用 java 发送一个 SoapMessage。我一直在设置正确的标题时遇到问题,确切地说是内容类型的部分,它应该是这样的:

Content-Type: multipart/related; type="application/xop+xml"; start="<rootpart@soapui.org>"; start-info="text/xml"; boundary="the boundary of my soapmessage"

我不知道如何将边界参数添加到我的标题中,以便它与soap 消息的其余部分相匹配。 我的肥皂消息看起来像这样:

------=_Part_0_5841104.1608651610791
Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
Content-Transfer-Encoding: 8bit
Content-ID: <rootpart@soapui.org>

MYXML

------=_Part_0_5841104.1608651610791

Content-Type: application/zip; name=Worker.zip
Content-Transfer-Encoding: binary
Content-ID: <MYFILE.zip>
Content-Disposition: attachment; name="MYFILE.zip"; filename="MYFILEr.zip"

MYATTACHMENT

soapbody 中的边界部分是自动生成的(------=_Part_0_5841104.1608651610791),每次我发送消息时它都会改变。当我尝试添加标题时,我是这样做的:

MessageFactory messageFactory = MessageFactory.newInstance(SOAPConstants.SOAP_1_1_PROTOCOL);
        SOAPMessage soapMessage = messageFactory.createMessage();
        SOAPPart soapPart = soapMessage.getSOAPPart();

    String authString = "login" + ":" + "password";
    String enc = java.util.Base64.getEncoder().encodeToString((authString).getBytes(StandardCharsets.UTF_8));
    MimeHeaders hd = soapMessage.getMimeHeaders();
    hd.addHeader("POST","where");
    hd.addHeader("Accept-Encoding","gzip,deflate");
    hd.addHeader("Content-Type","multipart/related; type=\"application/xop+xml\"; start=\"<rootpart@soapui.org>\"; start-info=\"text/xml\"; boundary=\"----=_????????\"");
    hd.addHeader("SOAPAction","Action");
    hd.addHeader("MIME-Version","1.0");
    hd.addHeader("Host","MyHost");
    hd.addHeader("Connection","Keep-Alive");
    hd.addHeader("User-Agent","Apache-HttpClient/4.1.1 (java 1.5)");
    hd.addHeader("Authorization","Basic " + enc);

如何将这个适当的边界添加到我的标题中?

解决方法

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