如何在 Python 中确定一年是闰年以及之后年份的天气？

问题描述

我必须编写一个for循环程序，要求用户输入年份和年数，首先确定输入的年份是否为闰年，其次输入此后的年数以检查这些是否也是闰年。

我的输出应该是这样的：

您想从哪一年开始？ 1994
您要检查多少年？ 8
1994年不是闰年
1995年不是闰年
1996年是闰年
1997年不是闰年
1998年不是闰年
1999年不是闰年
2000年是闰年
2001 年不是闰年

到目前为止，我的代码可以检查特定年份，但我正在努力循环它，以便它在此后的几年中继续。

这是我的代码：

print ("""Enter a year to see if it is a leap year,then enter the number of years there after you want to check""")

year_start = int(input("\nWhat year do you want to start with?\n"))
num_of_years = int(input("How many years do you want to check?\n"))

# I can't figure out the 'for loop' Syntax to loop this statement
if (year_start % 4) == 0:  
   if (year_start % 100) == 0:  
       if (year_start % 400) == 0:  
           print (f"{year_start} is a leap year")  
       else:  
           print (f"{year_start} isn't a leap year")  
   else:  
       print (f"{year_start} is a leap year")  
else:  
   print (f"{year_start} isn't a leap year")

解决方法

尝试将您的代码更改为：

print ("""Enter a year to see if it is a leap year,then enter the number of years there after you want to check""")

year_start = int(input("\nWhat year do you want to start with?\n"))
num_of_years = int(input("How many years do you want to check?\n"))

# I can't figure out the 'for loop' syntax to loop this statement
for i in range(year_start,year_start + num_of_years):
    if (i % 4) == 0:  
        print (f"{i} is a leap year")  
    else:  
       print (f"{i} isn't a leap year")

示例输出：

Enter a year to see if it is a leap year,then enter the number of years there after you want to check

What year do you want to start with?
1994
How many years do you want to check?
8
1994 isn't a leap year
1995 isn't a leap year
1996 is a leap year
1997 isn't a leap year
1998 isn't a leap year
1999 isn't a leap year
2000 is a leap year
2001 isn't a leap year

您可以使用 for 循环并使用 range 对序列进行迭代。那么你只需要(i % 4) == 0，你不需要其他条件。

仅除以 4 不足以找到闰年。你必须检查 100 和 400。

请检查 https://en.wikipedia.org/wiki/Leap_year#/media/File:Leap_Centuries.jpg 是否为闰年。

def is_leap_year(year: int) -> bool:
    # Returns True if the given year is a leap year
    return bool((not year % 400) or ((not year % 4) and year % 100))

使用 range(num_of_years) 如下：

for i in range(num_of_years):

您应该将所有闰年逻辑封装在 for 循环中并进行一些调整，但您应该能够自己计算出来，祝您好运。

python python-3.x