问题描述
好的，让我解释一下发生了什么我正在使用 tkinter 表单并正在填写正在填写的信息，我正在从包含电影的数据库中选择信息。我已经写了两次这段代码，一次是在没有从 tkinter 表单中获取信息的情况下编写的，然后第二次编写了从 tkinter 表单中获取的信息。我不确定错误来自哪里，因为代码没有改变。
这是运行正常的代码：
def PersonalityQuiz():
QuizUI = tk.Tk()
QuizUI.title("Personality Quiz")
QuizUI.geometry('700x300')
firstname = input("What is your first name?")
surname = input("What is your surname?")
answer1 = q1()
answer2 = q2()
answer3 = q3()
answer4 = q4()
answer5 = q5()
print(answer4,answer5)
sql = "SELECT * FROM Movies WHERE PG_rating <= %s AND Minutes <= %s AND Year >= %s AND Genre = %s AND Sub_Genre = %s ORDER BY imdb desc"
statement = (answer1,answer2,answer3,answer4,answer5)
sqlFilmID = "SELECT FilmID FROM Movies WHERE PG_rating <= %s AND Minutes <= %s AND Year >= %s AND Genre = %s AND Sub_Genre = %s"
mycursor = mydb.cursor()
mycursor.execute(sql,statement)
myresult = mycursor.fetchall()
listBox = tk.ListBox(QuizUI)
listBox.pack()
for i in myresult:
listBox.insert(tk.END,i)
mycursor.execute(sqlFilmID,statement)
FilmID = mycursor.fetchall()
sqlinsert = "INSERT INTO users (FirstName,Surname) VALUES (%s,%s)"
vals = (firstname,surname)
mycursor.execute(sqlinsert,vals)
mydb.commit()
UserID = mycursor.lastrowid
for i in FilmID:
LinkInsert = "INSERT INTO userlink (UserID,FilmID) VALUES (%s,%s)"
vals = (str(UserID),str(i[0]))
mycursor.execute(LinkInsert,vals)
mydb.commit()
QuizUI.mainloop()
def guiform():
genres = [
"Action","Adventure","Animation","Comedy","Crime","Documentry","Drama","Family","Fantasy","Horror","Musical","Sci-Fi","Spy","Superhero","War",] #etc
guitest = tk.Tk()
guitest.geometry("700x400")
frame1 = tk.Frame(master=guitest,height=200,width=100,bg="crimson")
frame1.pack(fill=tk.BOTH,side=tk.LEFT,expand=True)
values = tk.StringVar(guitest)
values.set(genres[0]) # default value
lblfirstname = tk.Label(frame1,text="First Name")
lblfirstname.grid(row=1,column=2)
ENTfirstname = tk.Entry(frame1)
ENTfirstname.grid(row=2,column=2)
lblsurname = tk.Label(frame1,text="Surname")
lblsurname.grid(row=3,column=2)
ENTsurname = tk.Entry(frame1)
ENTsurname.grid(row=4,column=2)
lbl1 = tk.Label(frame1,text="How old are you?")
lbl1.grid(row=1,column=0)
question1 = tk.Entry(frame1)
question1.grid(row=2,column=0)
lbl2 = tk.Label(frame1,text="What is the longest you would want a film to be? (minutes)")
lbl2.grid(row=4,column=0)
question2 = tk.Entry(frame1)
question2.grid(row=5,column=0)
lbl3 = tk.Label(frame1,text="What is the oldest year you would watch a movie from (e.g. 1985)")
lbl3.grid(row=6,column=0)
question3 = tk.Entry(frame1)
question3.grid(row=7,column=0)
lbl4 = tk.Label(frame1,text="What is your preferred Genre?")
lbl4.grid(row=8,column=0)
w = tk.OptionMenu(frame1,values,*genres)
w.grid(row=9,column=0)
submit = tk.Button(frame1,text="Submit information",command=lambda:infoget(question1.get,question2.get(),question3.get(),values.get()),width=18)
submit.grid(column=0,row=10)
listBox=tk.ListBox(frame1)
listBox.grid(row=0,column=1,rowspan=10)
def infoget(answer1,answer4):
sql = "SELECT * FROM Movies WHERE PG_rating <= %s AND Minutes <= %s AND Year >= %s AND Genre = %s ORDER BY imdb desc"
statement = (answer1,answer4)
mycursor = mydb.cursor()
mycursor.execute(sql,statement)
myresult = mycursor.fetchall()
for i in myresult:
listBox.insert(tk.END,i)
sqlFilmID = "SELECT FilmID FROM Movies WHERE PG_rating <= %s AND Minutes <= %s AND Year >= %s AND Genre = %s ORDER BY imdb desc"
mycursor.execute(sqlFilmID,statement)
FilmID = mycursor.fetchall()
sqlinsert = "INSERT INTO users (FirstName,%s)"
vals = (str(firstname),str(surname))
mycursor.execute(sqlinsert,vals)
mydb.commit()
#Returns the Primary Key of the last row accessed by the sql cursor
UserID = mycursor.lastrowid
for i in FilmID:
LinkInsert = "INSERT INTO userlink (UserID,%s)"
vals = (str(UserID),str(i[0]))
mycursor.execute(LinkInsert,vals)
mydb.commit()
guitest.update
guitest.mainloop()
这是它产生的可爱错误：
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\conversion.py",line 183,in to_MysqL
return getattr(self,"_{0}_to_MysqL".format(type_name))(value)
AttributeError: 'MysqLConverter' object has no attribute '_method_to_MysqL'
During handling of the above exception,another exception occurred:
Traceback (most recent call last):
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\cursor.py",line 432,in _process_params
res = [to_MysqL(i) for i in res]
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\cursor.py",in <listcomp>
res = [to_MysqL(i) for i in res]
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\conversion.py",line 185,in to_MysqL
raise TypeError("Python '{0}' cannot be converted to a "
TypeError: Python 'method' cannot be converted to a MysqL type
During handling of the above exception,another exception occurred:
Traceback (most recent call last):
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\tkinter\__init__.py",line 1884,in __call__
return self.func(*args)
File "Z:\My Files\Student My Documents\A Level\Computing\NEA\nea2.py",line 168,in <lambda>
submit = tk.Button(frame1,width=18)
File "Z:\My Files\Student My Documents\A Level\Computing\NEA\nea2.py",line 179,in infoget
mycursor.execute(sql,statement)
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\cursor.py",line 557,in execute
psub = _ParamSubstitutor(self._process_params(params))
File "C:\Users\lupin\AppData\Local\Programs\Python\python39\lib\site-packages\MysqL\connector\cursor.py",line 436,in _process_params
raise errors.ProgrammingError(
MysqL.connector.errors.ProgrammingError: Failed processing format-parameters; Python 'method' cannot be converted to a MysqL type
我不知道是什么造成和/或导致了这个错误。如果有人可以帮助解决此问题或为我指明解决此问题的正确方向，我将不胜感激！
谢谢你，卢平
解决方法
传递的第一个参数是下面一行中的一个函数：
command=lambda:infoget(question1.get,question2.get(),question3.get(),values.get())
应该是：
command=lambda:infoget(question1.get(),values.get())