问题描述
some_list = []
try:
while True:
... code that uses the list ...
except KeyboardInterrupt:
... code that modifies the list ...
处理完这个异常后,如何在不嵌套循环的情况下返回执行这个循环?
解决方法
您可以简单地重新构建代码以将循环与 try/catch
以这个为例:
from time import sleep
some_list = []
while True:
try:
print(some_list)
sleep(1)
except KeyboardInterrupt:
some_list.append("1")