问题描述
我是 R 的初学者。
point <- c("A","B","C","A","C")
Transit_A_B: 2;
Transit_A_C: 2;
Transit_B_C: 1;
Transit_B_A: 2;
Transit_C_B: 1;
Transit_C_A: 1.
非常感谢任何能帮助我的人。
解决方法
这可能会:
p1 <- head(point,-1)
p2 <- point[-1]
keep <- p1 != p2
table(paste0("Transit_",p1[keep],"_",p2[keep]))
#R>
#R> Transit_A_B Transit_A_C Transit_B_A Transit_B_C Transit_C_A Transit_C_B
#R> 2 2 2 1 1 1
如果你想要像你显示的那样打印输出:
p1 <- head(point,-1)
p2 <- point[-1]
keep <- p1 != p2
out <- table(paste0("Transit_",p2[keep]))
cat(paste0(names(out),": ",out,ifelse(seq_along(out) == length(out),".",";")),sep = "\n")
#R> Transit_A_B: 2;
#R> Transit_A_C: 2;
#R> Transit_B_A: 2;
#R> Transit_B_C: 1;
#R> Transit_C_A: 1;
#R> Transit_C_B: 1.
,
也许你可以像下面这样尝试embed
df <- rev(data.frame(embed(point,2)))
res <- table(
paste0(
"Transit_",do.call(paste,c(subset(df,do.call("!=",df)),sep = "_"))
)
)
给出
> res
Transit_A_B Transit_A_C Transit_B_A Transit_B_C Transit_C_A Transit_C_B
2 2 2 1 1 1
如果你更喜欢数据框格式的结果,你可以应用stack
而不是res
,例如,
> stack(res)
values ind
1 2 Transit_A_B
2 2 Transit_A_C
3 2 Transit_B_A
4 1 Transit_B_C
5 1 Transit_C_A
6 1 Transit_C_B