问题描述
在委托方法中传递的对象在实现协议的类中未初始化。但同一个对象在类中具有有效的地址,从那里调用委托。这仅在 maccatalyst 中发生,相同的代码在 iOS 和 iPadOS 中完美运行
协议声明
protocol ASPatientSearchDelegate: class {
func movetoPaitentProfileScreen(patient: ASCardEntity)
}
委托变量声明
weak var delegate: ASPatientSearchDelegate? = nil
委托调用
func tableView(_ tableView: UITableView,didSelectRowAt indexPath: IndexPath) {
let patient = self.searchResults[indexPath.row]
self.delegate?.movetoPaitentProfileScreen(patient: patient)
}
方法实现
extension ASAppointmentViewController: ASPatientSearchDelegate {
func movetoPaitentProfileScreen(patient: ASCardEntity) {
guard let json = patient.details as? JSON else { return }
}
}
在 AAsppointmentViewController 中分配的委托
@IBAction func searchButtonAction(_ sender: UIButton) {
let searchViewController = ASPatientSearchViewController(nibName: ASPatientSearchViewController.className,bundle: nil)
searchViewController.popoverPresentationController?.delegate = self
searchViewController.modelController.delegate = self
}
使用的类
class ASCardEntity: NSObject {
var details: Any?
}
解决方法
这是实例范围问题。我已将 ASPatientSearchViewController 实例变量声明为类范围
实例变量声明
class ASAppointmentViewController: ASBaseViewController {
var searchViewController: ASPatientSearchViewController?
}
我更改了下面的代码
@IBAction func searchButtonAction(_ sender: UIButton) {
let searchViewController = ASPatientSearchViewController(nibName: ASPatientSearchViewController.className,bundle: nil)
searchViewController.popoverPresentationController?.delegate = self
searchViewController.modelController.delegate = self
}
到
if self.searchViewController == nil {
self.searchViewController = ASPatientSearchViewController(nibName: ASPatientSearchViewController.className,bundle: nil)
}
self.searchViewController.popoverPresentationController?.delegate = self
self.searchViewController.modelController.delegate = self