问题描述
STREET_NAME | 位置 | CULVERT_TYPE | CULVERT_WIDTH | CULVERT_MATERIAL |
---|---|---|---|---|
主要街道 | 从 ST A 到 ST B | 下水道风暴\涵洞 | 1750 | 波纹钢管 |
SIDE ST | 从 ST C 到 ST D | 下水道风暴\涵洞 | 波纹钢管 | |
竞技场 1 | 下水道风暴\涵洞 | 300 | ||
下水道风暴\涵洞 | 500 | |||
. |
with cte as (
select 'MAIN ST' as STREET_NAME,'FROM ST A TO ST B' as LOCATION,'SEWER STORM \ CULVERT' as CULVERT_TYPE,1750 as CULVERT_WIDTH,'CORRUGATED STEEL PIPE' as CULVERT_MATERIAL
from dual
union all
select 'SIDE ST' as STREET_NAME,'FROM ST C TO ST D' as LOCATION,null as CULVERT_WIDTH,'CORRUGATED STEEL PIPE' as CULVERT_MATERIAL
from dual
union all
select null as STREET_NAME,'ARENA 1' as LOCATION,300 as CULVERT_WIDTH,null as CULVERT_MATERIAL
from dual
union all
select null as STREET_NAME,null as LOCATION,500 as CULVERT_WIDTH,'' as CULVERT_MATERIAL
from dual
union all
select null as STREET_NAME,null as CULVERT_TYPE,null as CULVERT_MATERIAL
from dual
)
select * from cte
我想将这些值连接到以竖线分隔的 |
列中(并忽略空值)。
CULVERT DESCRIPTION
----------------------
MAIN ST | FROM ST A TO ST B | SEWER STORM \ CULVERT | 1750 | CORRUGATED STEEL PIPE
SIDE ST | FROM ST C TO ST D | SEWER STORM \ CULVERT | CORRUGATED STEEL PIPE
ARENA 1 | SEWER STORM \ CULVERT | 300
SEWER STORM \ CULVERT | 500
<null>
问题:
有没有办法像在 Oracle 18c 中那样进行动态连接,同时忽略空值?
dyamic_concat( delimiter,parameters [ column1,column2,column3 ]... )
解决方法
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