抽象类中的数据库连接错误 - 有人帮我找到错误吗？

问题描述

有人帮我找出下面的代码有什么问题吗？ 我有 class student.PHP extends db.PHP。

Student.PHP

<?PHP
require_once('db.PHP');

class Student extends Db {
    
    public function __construct() {
        $res = $this->db_connect();
    }
}


$result = new Student();

db.PHP

<?PHP 
abstract class Db {
    protected $db_host;
    protected $db_user;
    protected $db_password;
    protected $db_name;
    public function __construct() {
        $this->db_host = 'localhost';
        $this->db_user = 'root';
        $this->db_password = '';
        $this->db_name = 'student';
    }
    protected function db_connect() {
        if(!isset($GLOBAL['db_connection'])) {
            $GLOBAL['db_connection'] = new MysqLi($this->db_host,$this->db_user,$this->db_password,$this->db_name);
        }
        
        if(MysqLi_connect_errno()) {
            $responseArray['status'] = '500';
            $responseArray['response'] = 'Error'. MysqLi_connect_error().' Error No: '. MysqLi_connect_errno();
        }
        else {
            $responseArray['status'] = '200';
            $responseArray['response'] = 'Database connection success';
        }
        
        return $responseArray;
    }
    
}

?>

返回结果

MysqLi::__construct(): (HY000/1045): Access denied for user ''@'localhost' (using password: NO)

我知道数据库变量是空的，这就是我收到错误的原因。但我需要确定代码有什么问题。

解决方法

您已覆盖 __construct() 方法，因此未设置默认值。 检查这个：

<?php
require_once('db.php');

class Student extends Db {
    
    public function __construct() {
        // call Db's constructor
        parent::__construct();

        $res = $this->db_connect();
    }
}