问题描述
如何从属性文件转换属性
creditmaster.metadata.AverageFicoScore=700
creditmaster.a.b.c=xyz
以通用的方式转换成这个json格式
{
creditmasterMetaData: [
{
attributeKey: "AverageFicoScore",attributeValue: 700
}
]
}
解决方法
这个脚本是通用的,因为键的部分是什么并不重要,它只按第一个元素(第一个点之前)和最后一个点之后的键名进行分组,它忽略了中:
%dw 2.3
output application/java
import * from dw::core::Strings
fun mapProperties(props) =
entriesOf(props) // since Mule 4.3 / DW 2.3
filter (substringAfter($.key,".") startsWith "metadata.") // to filter keys with .metadata.
groupBy ((item,index) -> substringBefore(item.key,"."))
mapObject ((value,key,index) ->
(key): value map {
attributeKey: substringAfterLast($.key,"."),attributeValue: if (isInteger($.value)) $.value as Number else $.value
}
)
---
mapProperties(payload)
输入文件:
creditmaster.metadata.AverageFicoScore= 700
other.a.b= 123
creditmaster.a.b.c=xyz
something.metadata.another.maximum=456
creditmaster.metadata.different.minimum=500
输出(为清晰起见,采用 JSON):
{
"something": [
{
"attributeKey": "maximum","attributeValue": "456"
}
],"creditmaster": [
{
"attributeKey": "minimum","attributeValue": "500"
},{
"attributeKey": "AverageFicoScore","attributeValue": "700"
}
]
}
,
另一种方法是使用 pluck
函数。它允许您迭代接收条目的对象。
如果你有这个输入
{
"creditmaster": {
"metadata": {
"AverageFicoScore": "700","OtherData": "Some value"
}
}
}
有了这个转变
{
creditmasterMetaData:
payload.creditmaster.metadata pluck ((value,index) ->
{
attributeKey: key,attributeValue: value
}
)
}
你得到这个输出
{
"creditmasterMetaData": [
{
"attributeKey": "AverageFicoScore","attributeValue": "700"
},{
"attributeKey": "OtherData","attributeValue": "Some value"
}
]
}