Mongoose 聚合不是错误：未显示特定季节电视的特定剧集且未填充

问题描述

我想知道代码有什么问题，为什么代码不起作用。

我喜欢这样的输出：

      {
        "seasons":
        [{

      "_id": "dhuhuasuhru8484r9r9ur","number": 2,"year": 2009,"episodes": [{
                     //only the specific episode,if I type 5 in the url,I must receive 5th episode 
                   and not all episodes

                 "id": "ruuhjbrrjrur9f887f88fds898","title": "universal stone","number": 5,"releasedOn": "2009-11-05T16:30:00.002Z","description": "Us"
                             "cast": [{
                                  "_id":"jfsijfju8u435ju35uh","fullName":"Joseph Sherlington","birthDate": "2012-02-10T15:00:00","genre":"male","nationality":"french"
                                  },{
                                        "_id":"uhhgb545h4nhhyuh","fullName":"Mathhiias toryn","birthDate": "2012-05-10T16:00:00","genre": "male","nationality":"german"

                                              }],"director":{
                                         "_id":"hjrhbh4h443h4h","fullName": "Alexis Sanders","nationality": "american"


                                            }


                                              }]
                                             }

                                           ]}

这是我的电视节目 routes.js：

             router.get("/showid/:tvShowId/episodenumber",tvShowsCtrl.getTvShowEpisode);

模型：

              const tvShowSchema = new Schema({

                           name: String,year: Number,country: String,seasons: [{

                                       number: Number,episodes:[{
                                              title: String,number: Number,releasedOn: Date,description: String,cast:[
                                                       {type: Schema.Types.ObjectId,ref:'actors'
                                                                }],director:{
                                                                type: Schema.Types.ObjectId,ref:'directors'
                                                                 }


                                                            },{timeStamps: true,versionKey: false

                                                           }

                                                              ]

                                                              }]

                                                      });

这是不填充也不显示特定季节的特定剧集时的电视节目控制器方法。我在 url 中使用一个 id 和查询以避免重复的 id：

                   export const getTvShowEpisode = async(req,res) =>{

                           try{

                            const { tvShowId } = req.params;

                            const { seasonId } = req.params;

                            const { episodeId } = req.params;


                             let selectedEpisode = null;
    
                                 const tvShowEpisode = await TVShow.aggregate([
            
            

                                      { $match:{

                                          "_id": Types.ObjectId(tvShowId),/* "seasons._id": Types.ObjectId(seasonId),"seasons.episodes._id": Types.ObjectId(episodeId),*/
                                          "seasons.number": req.query.seasonnumber,"seasons.episodes.number": req.query.number,}},// Does not populate

                         {$lookup: {from:'actors',localField: 'seasons.episodes.cast',foreignField: 
                         '_id',as: 'actors'}
                           },//Does not populate

                            {$lookup: {from:'directors',localField: 'seasons.episodes.director',foreignField: '_id',as: 'director'}},{$unwind: '$seasons'},{$match: {"seasons._id": Types.ObjectId(seasonId)}},{$project: {"_id": Types.ObjectId(tvShowId),"episode": "$seasons.episodes"}},]);

                                   if (tvShowEpisode) {
                                       res.send(tvShowEpisode);
                                       } else {
                                           res
                                           .status(404)
                                      .send({ mensaje: `tv show episode not found` });
                                           }

                                              }
                                         catch(error){
                                             console.log(error);
                                         res.status(500).send({message: `error: \n\n${error}`});
                                           }

                                 };

我在 postman 上得到的真正输出是虽然“200 OK Status”，但它返回的是空的并且不填充演员和导演。

我想知道我能做什么。没有console.log(err)的错误信息。

怎么了？

解决方法

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