问题描述
我想用 Spring Boot 实现 HATEOAS。我实现了它,现在我有另一个分页问题。我只想说分页是这样工作的:
{
"links": [
{
"rel": "first","href": "http://localhost:8080/api/posts?bookId=1&page=0&size=2"
},{
"rel": "self",{
"rel": "next","href": "http://localhost:8080/api/posts?bookId=1&page=1&size=2"
},{
"rel": "last","href": "http://localhost:8080/api/posts?bookId=1&page=1&size=2"
}
],"content": [
{
"id": 1,"bookId": 1,"title": "UpdatedPost1Title","content": "UpdatedPost1Content","created": "2021-01-18T20:42:39","updated": "2021-01-18T23:16:48","voteUp": 0,"voteDown": 0,"links": [
]
},{
"id": 2,"title": "title2","content": "content2","created": "2021-01-18T20:42:43","updated": "2021-01-18T20:42:43","links": [
]
}
],
但是正如你所看到的,我所有的内部“链接”都是空的。我运行了调试器,导致这种奇怪行为的行是:
PagedModel<EntityModel<PostDto>> page = pagedResourcesAssembler.toModel(postPage);
从这个方法:
@GetMapping
@ResponseStatus(HttpStatus.OK)
public ResponseEntity<PagedModel<EntityModel<PostDto>>> getPosts(@RequestParam(required = false) Long bookId,@PageableDefault(size = DEFAULT_PAGE_SIZE) Pageable pageable) {
Optional<Long> bookParam = Optional.ofNullable(bookId);
Page<PostDto> postPage = bookParam.map(aLong -> postService.getByBookId(aLong,pageable).map(assembler::toModel))
.orElseGet(() -> postService.getAllPosts(pageable).map(assembler::toModel));
PagedModel<EntityModel<PostDto>> page = pagedResourcesAssembler.toModel(postPage); //this line
return new ResponseEntity<>(page,HttpStatus.OK);
}
在此行之前,页面保留有关我之前添加的内部链接的信息 (assembler::toModel)。
我应该怎么做才能防止我的模型被 pagedResourcesAssembler 清除? (它是 org.springframework.data.web.PagedResourcesAssembler)。
先谢谢你!
解决方法
是的,我在这里找到了答案:https://howtodoinjava.com/spring5/hateoas/pagination-links/。它应该是这样的:
@GetMapping
@ResponseStatus(HttpStatus.OK)
public ResponseEntity<PagedModel<PostDto>> getPosts(@RequestParam(required = false) Long bookId,@PageableDefault(size = DEFAULT_PAGE_SIZE) Pageable pageable) {
Optional<Long> bookParam = Optional.ofNullable(bookId);
Page<Post> postPage = bookParam.map(aLong -> postService.getByBookId(aLong,pageable))
.orElseGet(() -> postService.getAllPosts(pageable));
PagedModel<PostDto> page = pagedResourcesAssembler.toModel(postPage,assembler);
return new ResponseEntity<>(page,HttpStatus.OK);
}
如您所见,PagedResourcesAssembler 应该是实体类型,而不是模型类型。我还在创建 PagedModel 之前删除了映射并使用 .toModel(Page,RepresentationModelAssembler) 方法。