问题描述
我的游戏运行正常,我对它的外观感到满意,我需要在游戏的每一行旁边添加 4 个指示器,以表明用户的猜测是否接近计算机的猜测
>游戏简介
如果用户猜到了颜色但位置错误,则应将指示器更改为橙色 如果它在正确的位置,它应该变成红色。然后用户用这个继续猜测
我想我可以在每一行旁边画 4 个圆圈,然后根据情况改变它们的颜色 来自用户的猜测。但是我不确定如何做到这一点
也可能有更有效的方法来做到这一点,所以有任何建议都会很棒
代码看起来像这样 我已经添加了一些代码,用于计算机猜测,如果你猜对了
import pygame
BLACK = (0,0)
WHITE = (255,255,255)
GREEN = (0,0)
RED = (255,0)
BLUE = (0,255)
WIDTH = 20
HEIGHT = 20
WIDTH1 = 30
HEIGHT1 = 30
MARGIN = 5
MARGIN1 = 10
array_width = 4
array_height = 8
grid = []
for row in range(10):
grid.append([])
for column in range(10):
grid[row].append(0)
colors = [(0,0) for i in range(array_width * array_height)]
blocks = [False for i in range(array_width * array_height)]
pygame.init()
# Set the HEIGHT and WIDTH of the screen
WINDOW_SIZE = [300,300]
screen = pygame.display.set_mode(WINDOW_SIZE)
# Set title of screen
pygame.display.set_caption("MASTERMIND GAME")
sair = True
done = False
clock = pygame.time.Clock()
# -------- Main Program Loop -----------
grid[row][column] = 1
#TEXT Box VARIABLES AND DATA
base_font = pygame.font.Font(None,32)
user_text = ""
input_rect = pygame.Rect (10,250,100,50)
color_active = pygame.Color('lightskyblue3')
color_passive = pygame.Color('gray15')
color=color_passive
active = False
current_color = "white"
grid = [[current_color for column in range(4)] for row in range(8)]
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
elif event.type == pygame.MOUSEBUTTONDOWN:
print (blocks)
pos = pygame.mouse.get_pos()
column = pos[0] // (WIDTH + MARGIN)
row = pos[1] // (HEIGHT + MARGIN)
print(row)
print(column)
# TEXT Box CREATION AND USAGE
# check if column and row are valid grid indices
if 0 <= row < array_height and 0 <= column < array_width:
try:
grid[row][column] = current_color
except:
print("invalid color")
if event.type == pygame.MOUSEBUTTONDOWN:
if input_rect.collidepoint(event.pos):
active = True
else:
active = False
if event.type == pygame.KEYDOWN:
if active == True:
if event.key == pygame.K_BACKSPACE:
user_text = user_text[0:-1]
else:
user_text += event.unicode
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_RETURN:
user_text = user_text
print(user_text)
if user_text != "":
current_color = user_text
user_text = ""
print("Click ",pos,"Grid coordinates: ",row,column)
if active:
color = color_active
else:
color=color_passive
screen.fill(0)
pygame.draw.rect(screen,color,input_rect,2)
text_surface= base_font.render(user_text,True,(255,255))
screen.blit(text_surface,(input_rect.x +5,input_rect.y + 5))
for row,gridrow in enumerate(grid):
for column,color in enumerate(gridrow):
pygame.draw.rect(screen,[(MARGIN + WIDTH) * column + MARGIN,(MARGIN + HEIGHT) * row + MARGIN,WIDTH,HEIGHT])
clock.tick(60)
pygame.display.flip()
pygame.quit
谢谢
解决方法
这个问题有几个子问题,我只回答了一个。因此,有很多机会从其他贡献者那里获得更多答案。
为指标创建一个新网格。所有字段的初始值为 None
:
indicator_grid = [[None for column in range(4)] for row in range(8)]
在嵌套循环中绘制指标:
while not done:
# [...]
for row,gridrow in enumerate(indicator_grid):
for column,status in enumerate(gridrow):
x = 100 + (MARGIN + WIDTH) * column + MARGIN
y = (MARGIN + HEIGHT) * row + MARGIN
color = "grey"
if status != None:
color = "red" if status else "orange"
pygame.draw.circle(screen,color,(x+WIDTH//2,y+WIDTH//2),WIDTH//2)
当您想将 indicator_grid
中的状态设置为 True
或 False
时,相应圆圈的颜色会发生变化。