问题描述
假设我们有一个如下所示的数据框：
我想使用pandas数据透视表以这种方式对其进行格式化：
然而，#include <cs50.h>
#include <stdio.h>
#include <string.h>
string sub(string plaintext,string cipher);
int main(int argc,string argv[])
{
string cipher = argv[1];
// checks for whether an argument was provided
if (argc != 2)
{
printf("Usage: ./substitution KEY\n");
return 1;
}
// checks for whether the cipher is 26 characters long
else if (strlen(cipher) != 26)
{
printf("Key must contain 26 characters\n");
return 1;
}
// makes sure the cipher contains only non-alphabetical characters
// also subtracts from 2015 (sum of all unique,upper-case letters) with each iteration to test for whether every character in the argument is unique
int sum = 2015;
for (int i = 0; i < strlen(cipher); i++)
{
if ((int) cipher[i] > 96 && (int) cipher < 123)
{
cipher[i] = (char) ((int) cipher[i] - 32);
}
if ((int) cipher[i] < 65 || ((int) cipher[i] > 90 && (int) cipher[i] < 97) || (int) cipher[i] > 122)
{
printf("Key must only contain alphabetical characters.\n");
return 1;
break;
}
sum -= ((int) cipher[i]);
}
// DEBUG: prints 'sum'
printf("%i\n",sum);
// THIS IS THE PROBLEM STATEMENT
// determines whether every character in the argument is unique
if (sum != 0)
{
printf("Key must contain all unique characters.\n");
return 1;
}
// gets the plaintext from the user and prints out the cipher text using the 'sub' function
string plaintext = get_string("plaintext: ");
printf("ciphertext: %s\n",sub(plaintext,cipher));
}
给了我一个看起来像这样的输出：
有人知道如何解决这个问题吗？
您可以使用以下代码来创建 df
df.pivot_table(index='Groupings',columns='columns',values=['value1','value2'])解决方法
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