如何根据句子制作带有多个列表的压缩 OrderedDict？

问题描述

我有六个列表，其中三个对应于给定的句子，另外三个列表对应于前面列表的标签。我想根据句子的顺序将这些列表压缩到 OrderedDict 中。

from collections import OrderedDict

sentence = 'Im fucking excited to learn your damn business'

words = ['excited','learn','business']
stopwords = ['Im','to','about','your']
swearwords = ['fucking','damn']

# Labels
words_labels = ['friendly','interested','interested']
stopwords_labels = ['stopword'] * len(stopwords)
swearwords_labels = ['sweaword'] * len(swearwords)

d = OrderedDict(zip(keys,values))

# Expected output
{
    'Im': 'stopword','fucking': 'swearword','excited': 'friendly','to': 'stopword','learn': 'interested','your': 'stopword'
    'damn': 'swearword','business': 'interested'
}

解决方法

先做一个重复内容的列表，语法是

stopwords_labels = ['stopword'] * len(stopwords)

然后建立所有内容和所有标签的列表，然后你就很好

keys = [*words,*stopwords,*swearwords]
values = [*words_labels,*stopwords_labels,*swearwords_labels]
mappings = dict(zip(keys,values))
d = OrderedDict((k,mappings[k]) for k in sentence.split())

您也可以使用这种连接语法

keys = words + stopwords + swearwords
values = words_labels + stopwords_labels + swearwords_labels