问题描述
我正在使用 Symfony 4.4 的安全包。
我的“用户”实体与 OnetoOne 上的“信息”实体相关。
以我的控制器为例(登录后)
当我使用 $this->getUser();
App\Entity\User\User {#1705 ▼
-id: 1
-email: "email@email.com"
-roles: array:1 [▶]
-password: "password"
-info: Proxies\__CG__\App\Entity\User\Info {#1716 ▼
+__isInitialized__: false
-id: 1
-firstname: null
-lastname: null
}
}
预期结果
App\Entity\User\User {#1705 ▼
-id: 1
-email: "email@email.com"
-roles: array:1 [▶]
-password: "password"
-info: Proxies\__CG__\App\Entity\User\Info {#1716 ▼
+__isInitialized__: true
-id: 1
-firstname: "Firstname"
-lastname: "Lastname"
}
}
在我身边
在我的守卫的 getUser
方法中,我使用 UserRepository
通过电子邮件查找我的用户。
// \App\Security\AppCustomAuthenticator
public function getUser($credentials,UserProviderInterface $userProvider)
{
// Load / create our user however you need.
// You can do this by calling the user provider,or with custom logic here.
$user = $this->userRepository->findUserByEmail($credentials['email']);
if (!$user) {
// fail authentication with a custom error
throw new CustomUserMessageAuthenticationException('User not found');
}
return $user;
}
// \App\Repository\User\UserRepository
public function findUserByEmail(string $email): ?User
{
return $this->createqueryBuilder('user')
->addSelect('user_info')
->leftJoin('user.info','user_info')
->andWhere('user.email = :email')
->setParameter('email',$email)
->getQuery()
->getoneOrNullResult()
;
}
但我在登录后丢失了实体 Info
数据。
登录后如何保留我的关系实体数据?
解决方法
我发现这是一个很好的问题,因为初学者确实经常遇到它。自定义提供程序和 getUser() 方法之间的联系并不总是很明显。
在应用程序中,用户通常并不孤单,他会提供地址、团队、尺寸、颜色和一包信息,这些信息随处可见,无需额外请求。
此链接适用于 Symfony 4.x https://symfony.com/doc/4.0/security/custom_provider.html
此链接对 Synfony 5.x 很有用
https://symfony.com/doc/current/security/user_provider.html#using-a-custom-query-to-load-the-user
我遇到了同样的问题,如果有人一直在寻找简单的解决方案。
使您的存储库实现 UserProviderInterface
,添加 3 个必需的方法(loadUserByUsername
、refreshUser
和 supportsClass
),修改 loadUserByUsername
方法以加入想要 Doctrine 关系并修改 security.yaml 以使用您的 UserRepository 作为自定义提供程序。
# src/Repository/UserRepository.php
<?php
namespace App\Repository;
use App\Entity\User as UserEntity;
use Doctrine\Bundle\DoctrineBundle\Repository\ServiceEntityRepository;
use Doctrine\Persistence\ManagerRegistry;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Symfony\Component\Security\Core\User\PasswordUpgraderInterface;
use Symfony\Component\Security\Core\User\User;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
/**
* @method null|UserEntity find($id,$lockMode = null,$lockVersion = null)
* @method null|UserEntity findOneBy(array $criteria,array $orderBy = null)
* @method UserEntity[] findAll()
* @method UserEntity[] findBy(array $criteria,array $orderBy = null,$limit = null,$offset = null)
*/
class UserRepository extends ServiceEntityRepository implements PasswordUpgraderInterface,UserProviderInterface
{
/**
* UserRepository constructor.
*/
public function __construct(ManagerRegistry $registry)
{
parent::__construct($registry,UserEntity::class);
}
public function upgradePassword(UserInterface $user,string $newEncodedPassword): void
{
if (!$user instanceof User) {
throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.',\get_class($user)));
}
$user->setPassword($newEncodedPassword);
$this->_em->persist($user);
$this->_em->flush();
}
public function loadUserByUsername($username)
{
return $this->createQueryBuilder('u')
->select('u,i')
->leftJoin('u.info','i')
->where('u.username = :username')
->setParameter('username',$username)
->getQuery()
->getOneOrNullResult();
}
public function refreshUser(UserInterface $user)
{
return $this->loadUserByUsername($user->getUsername());
}
public function supportsClass($class)
{
return \App\Entity\User::class === $class;
}
}
# config/packages/security.yaml
security:
encoders:
# ...
providers:
app_user_provider:
id: App\Repository\UserRepository
firewalls:
# ...
access_control:
# ...