问题描述
在此示例代码中,有时“差异”为 0。如何删除差异为 0 的“语句”? (详情见下文)
classlist = ['CLASS1','CLASS2','CLASS3','CLASS4','CLASS5','CLASS6','CLASS7']
gradelist1 = ['69.8','73','89','0','93','57']
gradelist2 = ['95.3','79','84','68','63']
def gradeChangeShow():
difference = []
try:
for i in range(len(gradelist1)):
difference.append(int(float(gradelist2[i])) - float(gradelist1[i]))
difference = ["{:.1f}".format(x) for x in difference]
except ValueError:
difference.append('0')
difference = [x for x in difference if x != '0']
statement = [f'\n{c.rstrip()}: {d}' for c,d in zip(classlist,difference)]
comma_delete = ','.join(statement)
return comma_delete.replace(',','')
print(gradeChangeShow())
上面的代码是这样的:
CLASS1: 25.2
CLASS2: 6.0
CLASS3: -5.0
CLASS4: 0.0
CLASS5: -25.0
CLASS6: 6.0
我希望它如何出来:
CLASS1: 25.2
CLASS2: 6.0
CLASS3: -5.0
CLASS5: -25.0
CLASS6: 6.0
解决方法
当您尝试过滤结果时,您使用整数 0
值作为目标。由于您的值是带小数点的字符串,因此这永远无法为您工作。
相反,请确保您与相同的类型进行比较。您可以针对 '0.0'
进行过滤,但是如果您更改了字符串中的精度,这将失败。我建议您将值转换为数字,然后进行比较。
statement = [f'\n{c.rstrip()}: {d}'
for c,d in zip(classlist,difference) if float(d) != 0]
输出:
CLASS1: 25.2
CLASS2: 6.0
CLASS3: -5.0
CLASS5: -25.0
CLASS6: 6.0