问题描述
d = {'award1' : { 'nominees': ['name1','name2'],'presenters': ['name3','name4'],'winner' : 'name1'
}
'award2' : { 'nominees': ['name5','name6'],'presenters': ['name7','name8'],'winner' : 'name6'
}
}
我正在尝试创建一个分隔值的字典列表,即结果应该是:
my_list = [ { 'award1': ['name1','award2': ['name5','name6'] },{ 'award1': ['name3','award2': ['name7','name8'] },{ 'award1': 'name1','award2': 'name6' }
]
有没有办法通过单行列表理解来做到这一点?
到目前为止我尝试过的:
lst = [{key:val['nominees'],key:val['presenters'],key:val['winner']} for key,val in d.items()]
我的代码使用普通的“for”循环:
nominees,winner,presenters = {},{},{}
for key,val in d.items():
nominees[key] = val['nominees']
winner[key] = val['winner']
presenters[key] = val['presenters']
lst = [nominees,presenters]
解决方法
这是一个列表推导 + 字典推导版本的单行代码来实现这一点:
d = {
'award1' : {
'nominees': ['name1','name2'],'presenters': ['name3','name4'],'winner' : 'name1'
},'award2' : {
'nominees': ['name5','name6'],'presenters': ['name7','name8'],'winner' : 'name6'
}
}
# List of keys to maintain the order of elements in the desired list
nested_keys = ['nominees','presenters','winner']
# In Python 3.7+: If the insertion order of key in initial dict is same as
# order of desired list,we can use this to make it more generic
# nested_keys = list(d.values())[0].keys()
new_list = [{k: d[k][key] for k in d.keys()} for key in nested_keys]
new_list
的位置:
[
{'award1': ['name1','award2': ['name5','name6']},{'award1': ['name3','award2': ['name7','name8']},{'award1': 'name1','award2': 'name6'}
]