问题描述
我正在尝试使用列表理解从列表中的所有字典中获取具有所有属性的格式化字符串
results = [{'TTL': '1643410114','customer': '1212','date': '2021-01-28','file': 'file.gz'}]
print("***** SEARCH RESULTS ***** \n".join([ f"{key}: {value}\n" for key,value in obj.items() for obj in results ]))
我得到了 NameError: name 'obj' is not defined
,我尝试了一些组合但没有成功,我该如何存档?
解决方法
您的内联 for 循环顺序错误:
>>> [ "{}: {}\n".format(key,value) for obj in results for key,value in obj.items() ]
['customer: 1212\n','date: 2021-01-28\n','file: file.gz\n','TTL: 1643410114\n']
,
需要调换两个for循环的顺序。
results = [{'TTL': '1643410114','customer': '1212','date': '2021-01-28','file': 'file.gz'}]
print("***** SEARCH RESULTS ***** \n".join([ f"{key}: {value}\n" for obj in results for key,value in obj.items()]))
输出
TTL: 1643410114
***** SEARCH RESULTS *****
customer: 1212
***** SEARCH RESULTS *****
date: 2021-01-28
***** SEARCH RESULTS *****
file: file.gz
,
这里有一个方法可以做到...
print("***** SEARCH RESULTS *****")
print(str([k +' : '+ results[0][k] for k in results[0]]).replace('[','').replace(']','').replace(',','\n').replace("'",""))
,
results = [{'TTL': '1643410114','file': 'file.gz'},{'TTL': '1643410115','customer': '1312','date': '2021-02-27','file': 'file2.gz'}
]
#print(results)
for obj in results:
for key,value in obj.items():
if (key=='file'):
print(obj['TTL'],key,value)
output
1643410114 file file.gz
1643410115 file file2.gz